The heights of women aged 20 to 29 follow approximately the N(64, 2.72) distribution. Men the same age have heights distributed
as N(69.3, 2.84). What percent of young men are shorter than the mean height of young women?
1 answer:
The z-score for men at 64 inches is:
Using a standard normal distribution table, we can see that the cumulative probability for a z-score of -1.866 is 0.031.
The answer is 3.1%.
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Answer:
20=n
Step-by-step explanation:
Take 385 and subtract 85. You get 300. Divide 300 by 15n. You get 20.
20=n
If you want to double check, replace n with 20 so the equation is
C=(15x20)+85
Hope I help!
Answer:
The answer is 22 feet.hope you like answer
What is the interquartile range of the data set?<br>
{48, 50, 65, 60, 80, 42, 45, 50, 42, 55, 45}
Tcecarenko [31]
The answer would ether be 16.5 or 10. Sorry, I'm not sure haven't done interquartile range in a little while.
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Hope this helps! Please mark me Brainliest if it did! Have a nice day!
Step-by-step explanation:
Answer:
yes because they are similar triangle