Question

Write -3i+(3/4+2i)-(9/3+3i) as a complex number in standard form.

Answer 1

-3i+3/4+2i-9/3-3i=(3/4-9/3) +(-3i+2i-3i)=(3/4-3)+(-4i)=(3/4-12/4)-4i=
=-9/4-4i

Answer 2

Answer:

The complex number in standard form is given by:

              $-4i-\dfrac{9}{4}$

Step-by-step explanation:

The expression in terms of the complex number is given by:

          $-3i+(\dfrac{3}{4}+2i)-(\dfrac{9}{3}+3i)$

which is given by:

$-3i+(\dfrac{3}{4}+2i)-(3+3i)$

Now on opening the parentheses term we have:

$-3i+\dfrac{3}{4}+2i-3-3i$

( since, if the sign before the parentheses term is negative then the sign of each of the terms inside parentheses get's interchanged )

Now, on combining the like terms we have:

$-3i+2i-3i+\dfrac{3}{4}-3\\\\=-4i-\dfrac{9}{4}$