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MAVERICK [17]
3 years ago
14

The original cost of a lamp is $18.95 . The lamp is on sale for 75% off . How much will you pay ?

Mathematics
2 answers:
Aleonysh [2.5K]3 years ago
8 0

Answer:

$4.74

Step-by-step explanation:

We have been given that the original cost of a lamp is $18.95 . The lamp is on sale for 75% off.

The cost of lamp after sale would be 25% (100-75) of $18.95.

\text{The cost of lamp after sale}=\$18.95\times \frac{25}{100}

\text{The cost of lamp after sale}=\$18.95\times 0.25

\text{The cost of lamp after sale}=\$4.7375

\text{The cost of lamp after sale}\approx \$4.74

Therefore, you will have to pay $4.74 for the lamp.

gregori [183]3 years ago
7 0
18.95x0.75=14.2125

18.95-14.2125=4.73

You will pay $4.73
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Tamara makes 12 identical flower arrangements, each with 3 roses and some carnations. She uses a total of 96 flowers.
storchak [24]

Answer:

5 carnations in each arrangement

Total of 60 carnations used

Step-by-step explanation:

First calculate how many flowers are in each arrangement by dividing the total number of flowers by the number of arrangements:

96 ÷ 12 = 8

Given each arrangement has 3 roses, subtract 3 from 8 to find the number of carnations in each arrangement:

8 - 3 = 5

Therefore, there are 5 carnations in each arrangement

Total number of carnations used = 5 x 12 = 60

5 0
2 years ago
1. Write a two-column proof.
Alexandra [31]

Answer:

Check it below, please

Step-by-step explanation:

Hi there!

Let's prove segment AB is perpendicular to CD. Attention to the fact that a two column proof has to be concise. So all the comments can't be exhaustive, but as short as possible.

Let's recap: An isosceles triangle is one triangle with at least 2 congruent angles.

Statement                     Reason

\overline{AB} \cong \overline{AC}\\                     Given

\widehat{ACB} \:bisects\: \overline{AB}        Isosceles Triangle the altitude, the bisector coincide.          

\overline{AD} \cong \overline{DB}               Bisector equally divide a line segment into two congruent      

m\angle CDA =m \angle CBD=90^{\circ} Right angles, perpendicular lines.                  

\overline{CD}\perp \overline{AB}                    Perpendicular Line segment      

8 0
3 years ago
A financial advisor is analyzing a family's estate plan. The amount of money that the family has invested in different real esta
Pachacha [2.7K]

Answer:

The amount of money separating the lowest 80% of the amount invested from the highest 20% in a sampling distribution of 10 of the family's real estate holdings is $238,281.57.

Step-by-step explanation:

Let the random variable <em>X</em> represent the amount of money that the family has invested in different real estate properties.

The random variable <em>X</em> follows a Normal distribution with parameters <em>μ</em> = $225,000 and <em>σ</em> = $50,000.

It is provided that the family has invested in <em>n</em> = 10 different real estate properties.

Then the mean and standard deviation of amount of money that the family has invested in these 10 different real estate properties is:

\mu_{\bar x}=\mu=\$225,000\\\\\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{50000}{\sqrt{10}}=15811.39

Now the lowest 80% of the amount invested can be represented as follows:

P(\bar X

The value of <em>z</em> is 0.84.

*Use a <em>z</em>-table.

Compute the value of the mean amount invested as follows:

\bar x=\mu_{\bar x}+z\cdot \sigma_{\bar x}

   =225000+(0.84\times 15811.39)\\\\=225000+13281.5676\\\\=238281.5676\\\\\approx 238281.57

Thus, the amount of money separating the lowest 80% of the amount invested from the highest 20% in a sampling distribution of 10 of the family's real estate holdings is $238,281.57.

6 0
3 years ago
The scores on an achievement test are normaly distributed with mean µ = 100 and standard deviation σ = 100. What should the scor
ser-zykov [4K]

Answer:

the student should score atleast 229 to be among the top 10%.

Step-by-step explanation:

in terms of the normal distribution, and if the table that you're using calculates the area of the normal distribution from the mean to a point x, only then what we are actually finding the value 'x' at which the z-score is at 40% (the rest 50% is already skipped by the table)

P(0.4) = \dfrac{x - \mu}{\sigma}

after finding the the value at this z-score, we can find the value of x at which the score is in the top 10% range.

we can find the z-score either using a normal distribution table or calculator. (but be sure what area is it calculating)

looking at the table the closest value we can find is, 0.4015 at z = 1.29 ((it is above 40% because we want to be in the top 10% range)

P(0.4015) = \dfrac{x - 100}{100}

1.29 = \dfrac{x - 100}{100}

x = 1.29(100) + 100

x = 229

the student should score atleast 229 to be among the top 10%.

7 0
2 years ago
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