Answer:
1/3 is .333... so you can write .33.... or .33 with a line on top of the 3's
Step-by-step explanation:
.3 is in the tenths and .33 is in the hundredths place
Answer:
Step-by-step explanation:
log8 62 = x1
8^x1= 62
8^2 =64 >62 so <u>x1<2</u>
log7 50=x2
7^x2=50
7^2=49<50 so <u>x2>2</u>
we have, x1<2 and 2<x2
x1<2<x2
x1<x2
log8 62<log7 50
Answer:
1:3.5
sorry if I'm wrong I really know it but still serve them wrong
Step-by-step explanation:
42/6 but if you want to simplify, it's 7
Oh Foxy, Foxy, how totally debilitated you must be ! Try to relax. Nobody
enjoys a painful brain, and believe me, this problem is not worth it.
Let me put it to you this way: What if the problem said . . .
-- Demarcus has $8 more than his sister.
-- His sister has $4.
-- How much money ' M ' does Demarcus have ?
If your brain didn't hurt, you could quickly solve this right in there.
You would know that Demarcus' money ' M ' = 8 + 4 .
That's <em>almost </em>exactly what the problem <em>does</em> say.
Except it doesn't say he has "$8 more than his sister",
it says he has "at least" that much.
So you know that ' M ' is not exactly = 8 + 4, but that's the <u>least</u> it could be.
The actual amount of ' M ' is <u>more</u> than that.
Surely you can handle it from here, even with half of your brain
tied behind your back.
Take a good hard look at ' A ', and then go lie down.
