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mrs_skeptik [129]

2 years ago

9

75 percent of the sutdents in a school went on a field trip. If 285 students went on the trip, how any students are in the schoo

l

1 answer:

natita [175]2 years ago

8 0

Answer:

380

Step-by-step explanation:

285 / x = 75 / 100

Cross multiply 28500 = 75x

Divide by 75 380

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A local hamburger shop sold a combined total of 712 hamburgers and cheeseburgers on Tuesday. There were 62 more cheeseburgers so

hammer [34]

A local hamburger shop sold a total of 712 burgers on Tuesday

There are 62 more cheeseburgers than hamburgers

let cheeseburers = c
let hamburgers = h

h + 62 = c
c + h = 712

Plug in h + 62 for c

(h + 62) + h = 712
2h + 62 = 712
2h + 62 (-62) = 712 (-62)
2h = 650
2h/2 = 650/2
h = 325

There are 325 hamburgers sold on Tuesday

c = 325 + 62
c = 387

<em>There are 387 chesseburgers sold on tuesday </em>(in case you were wondering)

hope this helps

4 0

3 years ago

-2×-7y=30 <br>7×+4y=18 <br>×= <br>y=

Sati [7]

Answer:

Answer is -7 Hope this helps :D

Step-by-step explanation:

6 0

3 years ago

Michelle drove a total of 57.8 kilometers on saturday. she drove 23.5 kilometers from her house to the park. her next stop was t

zloy xaker [14]

47.5 need this to extend my answer

5 0

3 years ago

Convert 300 seconds to minutes. A) 5 minutes B) 15 minutes C) 30 minutes D) 150 minutes

Olin [163]

1 minute = 60 seconds

300 seconds / 60 seconds = 5 minutes

7 0

3 years ago

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An envelope contains three cards: a black card that is black on both sides, a white card that is white on both sides, and a mixe

Over [174]

Answer:

There is a 2/3 probability that the other side is also black.

Step-by-step explanation:

Here let B1: Event of picking a card that has a black side

B2: Event of picking a card that has BOTH black side.

Now, by the CONDITIONAL PROBABILITY:

$P(B_2/B_1 ) = \frac{P(B_1\cap B_2)}{P(B_1)}$

Now, as EXACTLY ONE CARD has both sides BLACK in three cards.

⇒ P (B1 ∩ B2) = 1 /3

Also, Out if total 6 sides of cards, 3 are BLACK from one side.

⇒ P (B1 ) = 3 /6 = 1/2

Putting these values in the formula, we get:

$P(B_2/B_1 ) = \frac{P(B_1\cap B_2)}{P(B_1)} = \frac{1}{3} \times\frac{2}{1} = \frac{2}{3}$

⇒ P (B2 / B1) = 2/3

Hence, there is a 2/3 probability that the other side is also black.

5 0

3 years ago