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nydimaria [60]
4 years ago
12

Explain how to find the distance from (23,3) to (23,7) and from (23,3) and (4,3).

Mathematics
1 answer:
Aleks04 [339]4 years ago
5 0
Use the distance formula.
√(x1-x2)²+(y1-y2)²
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An engineer is going to redesign an ejection seat for an airplane. The seat was designed for pilots weighing between 130 lb and
egoroff_w [7]

Answer:

a) P(140

P(0.036

P(0.036

b) P(140< \bar X

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(139,28.1)  

Where \mu=139 and \sigma=28.1

We are interested on this probability

P(140

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(140

And we can find this probability like this:

P(0.036

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.  

P(0.036

Part b

For this case we select a sample size of n =32. Since the distribution for X is normal then the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu=139, \frac{\sigma}{\sqrt{n}}=\frac{28.1}{\sqrt{32}}=4.97)

And the new z score would be:

Z=\frac{\bar X -\mu}{\sigma_{\bar x}}

P(140< \bar X

P(140< \bar X

5 0
3 years ago
Toby the cat had quite a day. Toby caught 14 mice and ate 9 of them. How many mice does Toby still HAVE TO eat?
schepotkina [342]

Answer:

5

Step-by-step explanation:

14-9 = 5

3 0
3 years ago
Read 2 more answers
Frank wants to build a garden with the dimensions below.
dexar [7]
Given:
Length = x + x + 3 = 2x + 3
Width = 2 + x 

Area = length * width 
91 ft² = (2x + 3) (2+x)
91 = 4x + 2x² + 6 + 3x
0 = 2x² + 7x + 6 - 91
0 = 2x² + 7x - 85

(2x + 17) ( x - 5)

x = -17/2 or  x = 5

Let x = 5 ; 

length = 2x + 3 = 2(5) + 3 = 13
width = 2 + x = 2 + 5 = 7

 Area = 13 x 7 = 91

Perimeter = 2(length + width)
Perimeter = 2(13 + 7)
Perimeter = 2(20)
Perimeter = 20 feet of fencing
7 0
3 years ago
Read 2 more answers
A box with an open top will be constructed from a rectangular piece of cardboard. The piece of cardboard is 10 inches wide and 1
kupik [55]

Answer:

Domain of the function is  { x : x∈R, x>0 } or (0,∞).

Step-by-step explanation:

It is given that the dimensions of a rectangular piece of cardboard are

Length = 14 inch

Width = 10 inch

The box will be constructed by cutting out equal squares of side x at each corner and then folding up the sides. So the dimensions of the box are

Length = 14-2x inch

Breadth = 10- 2x inch

Height = x inch

The volume of cuboid box is

V=length\times breadth \times height

The volume function of the box is

V=(14-2x)\times (10-2x)\times x

V=(14-2x)(10-2x)x

The volume function is V=(14-2x)(10-2x)x.

It is a polynomial function and domain of a polynomial function is all real numbers.

Here, x represents the height of the box. So, value of x must be a positive real number.

Domain of the function is

Domain = { x : x∈R, x>0 }

It can be written as (0,∞).

Therefore, domain of the function is  { x : x∈R, x>0 } or (0,∞).

5 0
3 years ago
Please help. I’ll mark you as brainliest if correct!!!!
aliya0001 [1]

Answer:

(-∞, -6] U [-2, ∞)

Step-by-step explanation:

To solve this, begin by factoring this quadratic equation into its factored form:

x² + 8x + 12 ≥ 0 becomes (x+6)(x+2) ≥ 0.

x = -6, and x = -2 are the zeros of this parabola. Therefore:

(-∞, -6] U [-2, ∞) are the parts of the graph above y = 0 because the graph

opens upward.

** Remember, when the '≥' sign is present, the

square brackets must be used.

8 0
3 years ago
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