90 tens hopefully this helped
Answer:
x = ![\frac{\sqrt[3]{468}}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B468%7D%7D%7B6%7D)
or x =~ -1.29399
Step-by-step explanation:
Calculate the product. x^2 * 6x = 6x^3
divide both sides by 6. x^3 = -13/6
Take the root of both sides. x = ![\frac{\sqrt[3]{468}}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B468%7D%7D%7B6%7D)
Answer:
We use Baye's theorem: P(A)P(B|A) = P(B)P(A|B)
with (A) being defective and
(B) marked as defective
we have to find P(B) = P(A).P(B|A) + P(¬A)P(B|¬A). .......eq(2)
Since P(A) = 0.1 and P(B|A)=0.9,
P(¬A) = 1 - P(A) = 1 - 0.1 = 0.9
and
P(B|A¬) = 1 - P(¬B|¬A) = 1 - 0.85 = 0.15
put these values in eq(2)
P(B) = (0.1 × 0.9) + (0.9 × 0.15)
= 0.225 put this in eq(1) and solve for P(B)
P(B) = 0.4
The sample space is:
(1, 1); (1, 2) - sum of 3; (1, 3); (1, 4); (1, 5) - sum of 6; (1, 6);
(2, 1) - sum of 3; (2, 2); (2, 3); (2, 4) - sum of 6; (2, 5); (2, 6);
(3, 1); (3, 2); (3, 3) - sum of 6; (3, 4); (3, 5); (3, 6) - sum of 9;
(4, 1); (4, 2) - sum of 6; (4, 3); (4, 4); (4, 5) - sum of 9; (4, 6);
(5, 1) - sum of 6; (5, 2); (5, 3); (5, 4) - sum of 9; (5, 5); (5, 6);
(6, 1): (6, 2); (6, 3) - sum of 9; (6, 4); (6, 5); (6, 6)
The answer is y = 35x + 20.
In order to find this, start with two ordered pairs. For the purpose of this problem, we'll use (1, 55) and (2, 90). Now we use the slope formula to find the value next to x in the equation.
m(slope) = (y2 - y1)/(x2-x1)
In this equation (x1, y1) is the first ordered pair and (x2, y2) is the second. Plug in to the equation and solve.
m = (90 - 55)/(2 - 1)
m = 35/1
m = 35
Now that we have the slope, plug that into the equation along with either point to find the intercept (the last number).
y = mx + b
55 = 35(1) + b
55 = 35 + b
20 = b
Now that we have the slope and intercept, we can use each to fill in those blanks.
y = 35x + 20