Answer:
20 gallons were used from the tank with the octane rating of 80.
Step-by-step explanation:
Given : One tank of gasoline has an octane rating of 140 and another tank of gasoline has an octane rating of 80. To obtain a mixture of 60 gallons with an octane rating of 120.
To find : How many gallons should be used from the tank with the octane rating of 80?
Solution : Let x be the volume of gas whose octane rating is 140 and
y be the volume of gas whose octane rating is 80.
Then, we form the equation as:
(1) 

or
.........[3]
(2) 
Now multiply equation (2) by 4
...........[4]
Subtract (4) from (3)



Put x in equation [4] we get,





Therefore, x=40 and y=20
So, 20 gallons were used from the tank with the octane rating of 80.
Answer:
The equation has no solutions .
Step-by-step explanation:
Given as :
<u>The linear equation is </u>
(24 -16 x) =
(18 x -27)
Or,
×24 -
× 16 x =
× 18 x -
× 27
Or,
×24 -
× 16 x =
× 18 x +
× 27
Or,
-
=
+
Or, 3 × 6 - 3 × 4 x = - 2 × 6 x + 2 × 9
Or, 18 - 12 x = - 12 x + 18
Or, 18 - 18 = - 12 x + 12 x
or, 0 = 0
∵ The linear equation has no variables , so the equation has no solution
Hence,The equation has no solutions . Answer
Answer:
5 miles per hour
Step-by-step explanation:
15/3=5
Answer:
Step-by-step explanation:
8