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Shkiper50 [21]
3 years ago
13

Which transformation makes triangle 2 the image of triangle 1?

Mathematics
2 answers:
KATRIN_1 [288]3 years ago
7 0

Answer:

translation

Step-by-step explanation:

translation is just the movement of a shape, also stays the same size and way

Dahasolnce [82]3 years ago
3 0

Answer:a translation

Step-by-step explanation:

a translation means a slide therefore you just slide triangle 2 to be the same as triangle 1

brainliest?

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How can I calculate the value of x
AnnyKZ [126]
Solve 180=10x+10 to find your answer (:
8 0
3 years ago
Three rays have a common vertex on a line. Write and solve equations to find the measures of m and n
lukranit [14]

Answer:

n = 90 - 62

n = 28º

m = 180 - (62 + n + 27)

m = 180 - (62 + 28 + 27)

m = 180 - 117

m = 63º

5 0
3 years ago
Suppose that the Celsius temperature at the point (x, y) in the xy-plane is T(x, y) = x sin 2y and that distance in the xy-plane
liraira [26]

Missing information:

How fast is the temperature experienced by the particle changing in degrees Celsius per meter at the point

P = (\frac{1}{2}, \frac{\sqrt 3}{2})

Answer:

Rate = 0.935042^\circ /cm

Step-by-step explanation:

Given

P = (\frac{1}{2}, \frac{\sqrt 3}{2})

T(x,y) =x\sin2y

r = 1m

v = 2m/s

Express the given point P as a unit tangent vector:

P = (\frac{1}{2}, \frac{\sqrt 3}{2})

u = \frac{\sqrt 3}{2}i - \frac{1}{2}j

Next, find the gradient of P and T using: \triangle T = \nabla T * u

Where

\nabla T|_{(\frac{1}{2}, \frac{\sqrt 3}{2})}  = (sin \sqrt 3)i + (cos \sqrt 3)j

So: the gradient becomes:

\triangle T = \nabla T * u

\triangle T = [(sin \sqrt 3)i + (cos \sqrt 3)j] *  [\frac{\sqrt 3}{2}i - \frac{1}{2}j]

By vector multiplication, we have:

\triangle T = (sin \sqrt 3)*  \frac{\sqrt 3}{2} - (cos \sqrt 3)  \frac{1}{2}

\triangle T = 0.9870 * 0.8660 - (-0.1606 * 0.5)

\triangle T = 0.9870 * 0.8660 +0.1606 * 0.5

\triangle T = 0.935042

Hence, the rate is:

Rate = \triangle T = 0.935042^\circ /cm

3 0
2 years ago
This is the full page plz help
Scorpion4ik [409]
Angle 1 is congruent to angles 3, 5, and/or 7

Angle 2 is congruent to angles 4, 6, and/or 8

Angle 5 is congruent to angles 7, 3 and/or 1

Angle 6 is congruent to angles 8, 4, and/or 2

Any of these answers could work for the blanks.


Angles 1 and 3, 2 and 4, 5 and 7, and angles 6 and 8 are congruent because they are vertical angles. They have the same vertex. Not all of these are congruent to each other if this doesn’t make sense. It’s only 1 is congruent to 3, 2 congruent to 4, etc.

Then you have your corresponding angles. These are ones like angles 2 and 6, then 1 and 5. You can also have 8 and 4, or 7 and 3 as corresponding angles

Transversal angles are different. This would be like angles 3 and 4, or 1 and 2. They are not always congruent. The only time they will be congruent is if they are both 90°. Transversal angles are essentially supplementary angles on the transversal line (the line that intersects through the set of parallel lines)












3 0
3 years ago
Round 254 212 610 to the nearest million
mafiozo [28]

Answer:

254,000,00

I hope this helps

6 0
2 years ago
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