Answer:
or 
Step-by-step explanation:
Using the zero product property, first step is to set the given equation,
, to zero. Then factorise the left side.
Thus,

Subtract 2 from both sides


Factorise the left side



Find the solution

Or

Or



The answer is:
or 
<h2>
Answer:</h2>

<h2>
Step-by-step explanation:</h2>
If resistors are in series, so the current
is the same in all of them. In this problem we have four resistors. So, we can get a relationship between the Equivalent resistance of series combination and the four resistors as follows:

is the total resistance
. Moreover:

Therefore:

Answer:
- Commutative Property of Addition.-
- 2 + 3 = 3 + 2
- Commutative Property of Multiplication.- ex. 5 × 7 = 7 × 5
- Associative Property of Addition.- ex.(2 + 3) + 6 = 2 + (3 + 6)
- Associative Property of Multiplication.- ex. (7 × 3) × 10 = 7 × (3 × 10)
- Distributive Properties of Addition Over Multiplication- ex. 2 × (2 + 8) = 2 × 2 + 2 × 8
- (2 + 8) × 10 = 2 × 10 + 8 × 10
- The reciprocal of a non zero real number a is 1/a.- ex. reciprocal of 5 is 1/5 and 5 × (1/5) = 1
Step-by-step explanation:
Answer:
x = 12
Step-by-step explanation:
5x - 30 = 2x + 6
3x = 36
x = 12