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3 years ago

Write the polynomial in standard form. Then name it based on its degree and number of terms 2-11x^2-8x+6x^2

Mathematics

1 answer:

Elza [17]3 years ago

8 0

Answer: Is A

Step-by-step explanation:

-5x^2-8x+6x^2

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Which situation has the greatest rate of change? Filling a swimming pool with 100 gallons of water in 15 minutes or pumping 12 g

viktelen [127]

Answer:

Pumping gas into take with greater rate of change.

Step-by-step explanation:

Rate of change is equal to change in number of gallons per minutes.

Here we have two case

Case 1: Filling swimming pool with 100 gallons of water in 15 minutes.

So, we find how many gallons fill in 1 minutes.

$\text{Rate }=\frac{\text{Number of gallons}}{\text{Total minutes}}$

$\text{Rate }=\frac{100}{15}\approx 6.67\text{ gallons/min}$

Case 2: Pumping 12 gallons of gas into tank in 3 minutes.

So, we find how many gallons fill in 1 minutes.

$\text{Rate }=\frac{\text{Number of gallons}}{\text{Total minutes}}$

$\text{Rate }=\frac{12}{3}\Rightarrow 4\text{ gallons/min}$

Rate of case 2 is greater than case 1.

Thus, Pumping gas into tank with greater rate of change.

8 0

3 years ago

Solve the following systems of equations by graphing. Write your answer in the form of (x, y).

EastWind [94]

Answer:

(x,y) = (1,9)

Step-by-step explanation:

y = x + 8 and y = 5x + 4

3 0

3 years ago

Please help!!!!!!!!!!!!!!!!!

Vlada [557]

The answer is g or b

8 0

3 years ago

In the diagram below, OM is an altitude of right triangle PQR, PM = 8, and RM = 18.

xz_007 [3.2K]

Answer:

it is 12

Step-by-step explanation:

i don't kow but i think 12

7 0

3 years ago

An aquarium with a square base has no top. There is a metal frame. Glass costs 8 dollars/m^2 and the frame costs 7 dollars/m. Th

Irina-Kira [14]

Given that the volume of the aquarium is 20m^3.

Volume = Area of Base x height

Area of Base = Volume / height = 20/h

Given that the aquarium has a square base.

Area of square = l^2

Thus, the length of the base of the aquarium is $\sqrt{area \ of \ base} = \sqrt{ \frac{20}{h} }$

The frame is to cover 8 sides with the length equal to the length of the base and 4 sides with the length of the height.

Thus, the total perimeter of the frame is given by $8\sqrt{\frac{20}{h}}+4h= \sqrt{64\left(\frac{20}{h}\right)}+4h = \sqrt{\frac{1,280}{h}}+4h$

Area of the four side faces of the aquarium is 4 times the length of the base times the height = $4\times\sqrt{ \frac{20}{h} }\times h=\sqrt{16\left(\frac{20}{h}\right)h^2}=\sqrt{320h}$

Total area to be covered by grass is the base and the four side faces and is given by $\frac{20}{h}+\sqrt{320h}$

Cost of the entire metal frame = $7\left(\sqrt{\frac{1,280}{h}}+4h\right)= \sqrt{49\left(\frac{1,280}{h}\right)}+7(4h) = \sqrt{\frac{62,720}{h}}+28h$

Cost of the entire grass = $8\left(\frac{20}{h}+\sqrt{320h}\right)=\frac{160}{h}+\sqrt{64(320h)}=\frac{160}{h}+\sqrt{20,480h$

Therefore, total cost in terms of the height, h, is given by

$C=\sqrt{\frac{62,720}{h}}+28h+\frac{160}{h}+\sqrt{20,480h$

3 0

4 years ago