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3 years ago

I've heard about Naruto. Should I watch?

Mathematics

2 answers:

Aleksandr-060686 [28]3 years ago

6 0

Answer:

It depends.

Step-by-step explanation:

If your more focused with school work, don't do it because you will start to watch more and more. And then Bam! No more time for school work. So don't watch if your constantly worried about grades. Trust me.

viktelen [127]3 years ago

4 0

Answer:yes

Step-by-step explanation:

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Which is the graph of 2x + 3y >-3?

Cerrena [4.2K]

Answer:

The third graph is correct for the inequality 2x + 3y > -3

Step-by-step explanation:

The slope of the graph is –2/3.

The y-intercept is –1

The area above the dashed be line is shaded.

To verify, choose a coordinate in the shaded area, substitute the values for x and y. Calculate and check.

For example: (1,1)

2(1) + 3(1) > –3

2 + 3 > –3

5 > –3 True.

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3 years ago

Whats the answer for 8,9,10?<br><br> thanks to the people who answer<3

butalik [34]

Step-by-step explanation:

here is the answer attached

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3 years ago

On the set of axes below graph the inequality 2x+y>1

alukav5142 [94]

Roughly something like this. The y intercept is at (0,1). The x intercept is at (-.5,0). Another point is at (1,3).

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3 years ago

Construct a line from A perpendicular to the x-axis, determine the distance from A to the x-axis along this perpendicular line,

Vaselesa [24]

Step-by-step explanation:

To determine distances, we need to use this formula: $d=\sqrt{(y_{2}-y_{1} ) ^{2} +(x_{2}-x_{1}) ^{2} }$

To apply that formula we need to use the coordinates of point, but in this case will be calculated generally, due to the lack of specific values.

So, Point A have the coordinates $(x_{1};y_{1})$

Let's call Point P the one that's on the x-axis, its coordinates are $(p_{1};q_{1})$

Applying the formula, the distance between this two points will be:

$d=\sqrt{(q_{1}-y_{1} ) ^{2} +(p_{1}-x_{1}) ^{2} }$

To find an opposite and equidistant point, we only need to use opposite values. So, let's call Point B, the opposite point, its coordinates will be:

$(-x_{1};-y_{1})$

And the distance will be the same, because squared values will always results positive.

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3 years ago

disregard question..............................................................................................................

Gnesinka [82]

Answer:

whats the question.

Step-by-step explanation:

let me know

7 0

3 years ago