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3 years ago

Given: DBC = RST Prove: ABC > RST

Mathematics

1 answer:

masya89 [10]3 years ago

5 0

Answer:

Step-by-step explanation:

Given < DBC = < RST and we need to prove < ABC is greater than <RST.

First given statement:

< DBC = < RST

Reason: Given.

Second given statement :

<ABC = <DBC+ <ABD.

Reason: Angle addition theorem.

Note: < ABC is the sum of angles <DBC and <ABD and we have < DBC = < RST. So it's an obvious thing that the sum of angles <DBC and <ABD is always greater than <RST.

Also, <ABC is greater than <DBC.

Therefore, correct option for third statement is :

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Step-by-step explanation:

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3 years ago

Read 2 more answers

A central angle of a circle measures 1.5 radians. If the radius of the circle is 3 cm, what is the area of the related sector?

soldi70 [24.7K]

Answer:

Option B. $6.75\ cm^{2}$

Step-by-step explanation:

we know that

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$A=\pi r^{2}$

we have

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substitute

$A=\pi (3^{2})=9 \pi\ cm^{2}$

Remember that

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by proportion

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Answer:

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Step-by-step explanation:

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