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3 years ago

Given: DBC = RST Prove: ABC > RST

Mathematics

1 answer:

masya89 [10]3 years ago

5 0

Answer:

Step-by-step explanation:

Given < DBC = < RST and we need to prove < ABC is greater than <RST.

First given statement:

< DBC = < RST

Reason: Given.

Second given statement :

<ABC = <DBC+ <ABD.

Reason: Angle addition theorem.

<em>Note: < ABC is the sum of angles <DBC and <ABD and we have < DBC = < RST. So it's an obvious thing that the sum of angles <DBC and <ABD is always greater than <RST.</em>

Also, <ABC is greater than <DBC.

Therefore, correct option for third statement is :

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2 years ago

Can someone help me with this?

Mariulka [41]

Answer:

1) $4+5=9$ .

2) $2+(-6)=-4$

3) $-3+(-7)=-10$

4) $(-7)+3=-4$

5) $9+(-4)=5$

6) $-1+4=3$

7) $5+(-5)=0$

8) $-3+(-6)=-9$

Step-by-step explanation:

In the given number lines, rightarrows represent positive integers and leftarrows represent negative integers.

In first number line we have two rightarrows.

Rightarrow from 0-4 = 4

Rightarrow from 4-9 = 5

So, required sum is $4+5=9$ .

Similarly,

$2+(-6)=-4$

$-3+(-7)=-10$

$(-7)+3=-4$

$9+(-4)=5$

$-1+4=3$

$5+(-5)=0$

$-3+(-6)=-9$

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3 years ago