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4 years ago

Solve for h. a = ch + f

2 answers:

4 0

Hello there ^ _ ^

a = ch + f
Solve for h
ch = f - a
Now we just need to divide both sides by c
ch/c = f-a/ c
h = ( a - f)/c

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tankabanditka [31]4 years ago

3 0

It would be a - f / c = h

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ollegr [7]

Answer:

Step-by-step explanation:

1+0=1

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4 years ago

Read 2 more answers

Use the quadratic formula to solve the equation 2x^2+2x-4=0

const2013 [10]

Answer:

Step-by-step explanation:

The quadratic formula for the quadratic equation ax² + bx + c = 0:

$x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$2x^2+2x-4=0\qquad\text{divide both sides by 2}\\\\x^2+x-2=0$

$a=1,\ b=1,\ c=-2$

Substitute:

$x=\dfrac{-1\pm\sqrt{1^2-4(1)(-2)}}{2(1)}=\dfrac{-1\pm\sqrt{9}}{2}=\dfrac{-1\pm3}{2}\\\\x_1=\dfrac{-1-3}{2}=\dfrac{-4}{2}=-2\\\\x_2=\dfrac{-1+3}{2}=\dfrac{2}{2}=1$

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3 years ago

HELP. Put these in order from least to greatest

Naily [24]

Look at each number and see which has the greatest value and which has the least then just put the smallest first then work your way to the greatest value.

5 0

4 years ago

Example 1: Calculation of Normal Probabilities Using ????????-Scores and Tables of Standard Normal Areas The U.S. Department of

Molodets [167]

Answer:

i) 0.872

ii) 0.300

iii) 0.76

iv) 0.704

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = $261.50 per month

Standard Deviation, σ = $16.25

We are given that the distribution of monthly food cost for a 14- to 18-year-old male is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(Less than $280)

$P( x < 280) = P( z < \displaystyle\frac{280 - 261.50}{16.25}) = P(z< 1.138)$

Calculation the value from standard normal z table, we have,

$P(x < 280) = 0.872 = 87.2\%$

b) P(More than $270)

P(x > 270)

$P( x > 270) = P( z > \displaystyle\frac{270 - 261.50}{16.25}) = P(z > 0.523)$

$= 1 - P(z \leq 0.523)$

Calculation the value from standard normal z table, we have,

$P(x > 270) = 1 - 0.700 = 0.300 = 30.0\%$

c) P(More than $250)

P(x > 250)

$P( x > 250) = P( z > \displaystyle\frac{250 - 261.50}{16.25}) = P(z > -0.707)$

$= 1 - P(z \leq -0.707)$

Calculation the value from standard normal z table, we have,

$P(x > 250) = 1 - 0.240 = 0.76 = 76.0\%$

d) P(Between $240 and $275)

$P(240 \leq x \leq 275) = P(\displaystyle\frac{240 - 261.50}{16.25} \leq z \leq \displaystyle\frac{275-261.50}{16.25}) = P(-1.323 \leq z \leq 0.8307)\\\\= P(z \leq 0.8307) - P(z < -1.323)\\= 0.797 - 0.093 = 0.704 = 70.4\%$

$P(240 \leq x \leq 275) = 70.4\%$

e) Thus, 0.704 is the probability that the monthly food cost for a randomly selected 14- to 18-year-old male is between $240 and $275.

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3 years ago

Convert an area of 36inces (in2) to square centimeters (cm2) rounded to 1 decimal place

tia_tia [17]

232.3 square centimeters

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3 years ago