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4 years ago

9

since this was my first time you guys are in for a treat .... FREE POINTS answer question " 1+0 " don't for get to friend me :)

see y'all next week

2 answers:

ollegr [7]4 years ago

6 0

Answer:

1

Step-by-step explanation:

1+0=1

irina1246 [14]4 years ago

3 0

Hii 1+0=1 sorry don’t know to friend:(

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Need ASAP<br><br> Evaluate h^-2 g for h = 3 and g = 27.<br><br> 9<br> 3<br> 1/3

tangare [24]

Answer:

3

Step-by-step explanation:

h^-2 g

h= 3 and g = 27

(3) ^-2 (27)

1/3^2 (27)

1/9 *27

27/9

3

5 0

3 years ago

The area of a triangle is the product of the base of the triangle times the height of the triangle, divided by two.

Natali [406]

Answer:

A = (1/2)(base)(height)

Step-by-step explanation:

Yes, that's correct:

A = (1/2)(base)(height)

Was there more to this question?

3 0

3 years ago

ATTENTION: Please help! I will give BRAINLIEST to who ever is right AND will give 10 points AND 5 more from BRAINLIEST.

posledela

3rd one from (left to right)

8 0

3 years ago

Ellus<br> What is the measure of z?<br> 4<br> 16<br> z<br> X<br> Z =<br> ✓ [?]

Sholpan [36]

Answer:

$z=\sqrt{80}$

Step-by-step explanation:

By geometric mean property:

$y= \sqrt {16\times 4}$

$y= \sqrt {64}$

$y= 8$

By Pythagoras Theorem:

$z=\sqrt{4^2 +8^2}$

$z=\sqrt{16 + 64}$

$z=\sqrt{80}$

8 0

3 years ago

An urn contains two black balls and three red balls. If two different balls are successively removed, what is the probability th

lidiya [134]

You can extract two balls of the same colour in two different way: either you pick two black balls or two red balls. Let's write the probabilities of each pick in each case.

Case 1: two black balls

The probability of picking the first black ball is 2/5, because there are two black balls, and 5 balls in total in the urn.

The probability of picking the second black ball is 1/4, because there is one black ball remaining in the urn, and 4 balls in total (we just picked the other black one!)

So, the probability of picking two black balls is

$P(\text{two blacks}) = \dfrac{2}{5} \cdot \dfrac{1}{4} = \dfrac{2}{20} = \dfrac{1}{10}$

Case 2: two red balls

The probability of picking the first black ball is 3/5, because there are three red balls, and 5 balls in total in the urn.

The probability of picking the second red ball is 2/4=1/2, because there are two red balls remaining in the urn, and 4 balls in total (we just picked the other red one!)

So, the probability of picking two red balls is

$P(\text{two reds}) = \dfrac{3}{5} \cdot \dfrac{1}{2} = \dfrac{3}{10}$

Finally, the probability of picking two balls of the same colour is

$P(\text{same colour}) = P(\text{two blacks})+ P(\text{two reds}) = \dfrac{1}{10} + \dfrac{3}{10} = \dfrac{4}{10} = \dfrac{2}{5}$

7 0

3 years ago