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4 years ago

Find the measure of each exterior angle of a regular 56-gin

1 answer:

Studentka2010 [4]4 years ago

3 0

The sum of the measure of the exterior angles of any polygon is 360. x represents the measure of a single exterior angle.
360/56=x
The simplified fraction is 45/7

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What is 2.26 (6 repeating) as a fraction?

Gekata [30.6K]

Answer:

34/15

Step-by-step explanation:

I recognized the form of this decimal as a number divided by 3. However, when I multiplied it by 3, I got 6.8. This means that the fraction was not fully simplified. Multiplying by 5, I got 34. Since I had to multiply by 3 and then by 5 to get there, I multiplied by a total of 15. Hope this helps!

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4 years ago

Consider the function below. Find f(5)

Alex73 [517]

Answer:

-3

Step-by-step explanation:

f(x)=-2x+7

f(5)=-2×5+7

=-10+7

=-3

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3 years ago

A teacher and a doctor each have 45 books. If 4/5 f the teacher's books and 2/3 of the doctor's books are novels, how many more

Anarel [89]

Answer:

3/5

Step-by-step explanation:

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3 years ago

A recipe requires 3 cups of flour to make 27 dinner rolls. How much flour is needed to make 9 rolls?

Rudik [331]

It takes 1 cup of flour.

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3 years ago

Read 2 more answers

Find sinϴ and cosϴ if tanϴ=1/4 and sinϴ>0

eduard

If you're using the app, try seeing this answer through your browser: brainly.com/question/2787701

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$\mathsf{tan\,\theta=\dfrac{1}{4}\qquad\qquad(sin\,\theta\ \textgreater \ 0)}\\\\\\
\mathsf{\dfrac{sin\,\theta}{cos\,\theta}=\dfrac{1}{4}}\\\\\\
\mathsf{4\,sin\,\theta=cos\,\theta\qquad\quad(i)}$

Square both sides:

$\mathsf{(4\,sin\,\theta)^2=(cos\,\theta)^2}\\\\
\mathsf{4^2\,sin^2\,\theta=cos^2\,\theta}\\\\
\mathsf{16\,sin^2\,\theta=cos^2\,\theta\qquad\qquad(but,~cos^2\,\theta=1-sin^2\,\theta)}\\\\
\mathsf{16\,sin^2\,\theta=1-sin^2\,\theta}$

$\mathsf{16\,sin^2\,\theta+sin^2\,\theta=1}\\\\
\mathsf{17\,sin^2\,\theta=1}\\\\
\mathsf{sin^2\,\theta=\dfrac{1}{17}}\\\\\\
\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{1}{17}}}\\\\\\
\mathsf{sin\,\theta=\pm\,\dfrac{1}{\sqrt{17}}}$

Since $\mathsf{sin\,\theta}$ is positive, you can discard the negative sign. So,

$\mathsf{sin\,\theta=\dfrac{1}{\sqrt{17}}\qquad\quad\checkmark}$

Substitute this value back into $\mathsf{(i)}$ to find $\mathsf{cos\,\theta:}$

$\mathsf{4\cdot \dfrac{1}{\sqrt{17}}=cos\,\theta}\\\\\\
\mathsf{cos\,\theta=\dfrac{4}{\sqrt{17}}\qquad\quad\checkmark}$

I hope this helps. =)

Tags: <em>trigonometric identity relation trig sine cosine tangent sin cos tan trigonometry precalculus</em>

7 0

3 years ago