A coyote had 10 pups in her third litter. It was twice as many as in her second litter, her second litter, and her second litter
had 3 more pups than her first. Find the number of pups in her litter
1 answer:
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Answer:
∠ACB = 38°
Step-by-step explanation:
∠ACB is an inscribed angle while arcAB is its intercepted arc
An inscribed angle is equal to half the length of its intercepted arc
Hence, ∠ACB = 1/2 the measure of arc AB
arc AB = 76°
Hence ∠ACB = 1/2 of 76
76/2 = 38
Therefore ∠ACB = 38°
