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jekas [21]
3 years ago
9

Which relations are functions?

Mathematics
1 answer:
Alenkasestr [34]3 years ago
6 0
Both A, and C. are functions because they don't have two points with the same x-intercept.

Hope this helps!!
~Kiwi
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Find the exact value of the expression. Sin 265 cos 25 - cos 265 sin 25
DerKrebs [107]
Answer:

\sin(265\degree) \cos(25\degree)-\sin(265\degree) \cos(25\degree)=-\frac{\sqrt{3}}{2}

Step-by-step explanation:

Recall that;

\sin(A) \cos(B)-\sin(B) \cos(A)=\sin(A-B)

This implies that;

\sin(265\degree) \cos(25\degree)-\sin(265\degree) \cos(25\degree)=\sin(265\degree-25\degree)

\sin(265\degree) \cos(25\degree)-\sin(265\degree) \cos(25\degree)=\sin(240\degree)

\sin(265\degree) \cos(25\degree)-\sin(265\degree) \cos(25\degree)=\sin(180\degree+60\degree)

\sin(265\degree) \cos(25\degree)-\sin(265\degree) \cos(25\degree)=-\sin(60\degree)

\sin(265\degree) \cos(25\degree)-\sin(265\degree) \cos(25\degree)=-\frac{\sqrt{3}}{2}
4 0
3 years ago
A bicycle manufacturing company makes a particular type of bike. Each child bike requires 4 hours to build and 4 hours to test.
Verdich [7]

 the first option is the answer

Step-by-step explanation:

4c + 6a <= 120 [building hours]

4c + 4a <= 100 [testing hours]

4 * 20 + 6 * 6 <= 120

80 + 36 <= 120

116 <= 120

true, they have enough building hours

4 * 20 + 4 * 6 <= 100

80 + 24 <= 100

104 <= 100

false, they won't have enough testing hours

the first option is the answer

3 0
3 years ago
Please solve i and ii for me
KengaRu [80]

If you know the derivative f'(x) of some function f(x), you can tell exactly who f(x) is, up to an additive, constant term. In fact, knowing f'(x), you have

\displaystyle \int f'(x) = f(x)+c

In your case, we have

\dfrac{d}{dx} \sqrt{x+3} = \dfrac{1}{2\sqrt{x+3}}

So, the integral is almost immediate:

\displaystyle\int \dfrac{2}{\sqrt{x+3}} = \int \dfrac{4}{2\sqrt{x+3}} = 4\int\dfrac{1}{2\sqrt{x+3}} = 4\sqrt{x+3}+c

So, up to some constant additive term, our function is 4\sqrt{x+3}+c

To fix this constant, we know that the function passes through the point (6,10), so we have

f(6) = 4\sqrt{6+3}+c = 4\sqrt{9}+c=12+c=10 \iff c=-2

And so our function is 4\sqrt{x+3}-2

If we want to know when this function equals 6, we simply have to ask f(x)=6 and solve for x, so we have

4\sqrt{x+3}-2=6 \iff 4\sqrt{x+3} = 8 \iff \sqrt{x+3} = 2 \iff x+3=4 \iff x = 1

5 0
3 years ago
Kenley wants to show 1200 using only tens blocks. How many tens blocks does Kenley need?
user100 [1]
Divide by 10 to find how many tens he needs. 

1200/10 = 120

Answer: He needs 120 tens
3 0
3 years ago
Read 2 more answers
Please help need this done by tomorrow thank you [PHOTO]​
Ksenya-84 [330]

Answer:

Step-by-step explanation:

The two angles must add to 180

(4x-2)+(3x+14)=180

7x+12=180

7x=168

x=24

6 0
3 years ago
Read 2 more answers
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