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2 years ago

Please help me my teacher doesn't know how to teach

Mathematics

2 answers:

Akimi4 [234]2 years ago

6 0

Answer:

Whats the question

Step-by-step explanation:

Dovator [93]2 years ago

6 0

Answer:

There are videos on Khan Academy about this one

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How do u convert decimals to percents and percents to decimals????????

Oduvanchick [21]

Answer:

To convert a decimal to percent, just multiply it by 100, or move the decimal place 2 times

Ex: 0.29 x 100 = 29

The answer would be 29%

To convert a percent to a decimal, do the opposite

Ex: 29%/100 = 0.29

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3 years ago

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4. Uncle Rick, who is numbering seats at a wrestling arena, is assigned a section of 12 rows of

nydimaria [60]

Answer:

Step-by-step explanation:

Each rows contain 12 seats.

No.of seats in 12 rows = 12 *12 = 144 seats

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3 years ago

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The lakers scored a total of 80 points in a basketball game against the bulls. the lakers made a total of 37 two-point and three

11111nata11111 [884]

<span>The answer is 2 three-point shots. Since the Lakers made 37 two-point shots, one multiplies 37 by 2 (37 x 2), which equals 74. Then 74 is subtracted from the total 80 to see how many points are left (80 - 74), which equals 6. To determine the number of three-point shots, 6 is divided by 3 (6/3), which equals 2.</span>

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4 years ago

Ellus

butalik [34]

9514 1404 393

Answer:

2.25

Step-by-step explanation:

Add the square of half the x-coefficient to complete the square.

(-3/2)² = 9/4 = 2.25

4 0

3 years ago

Distance between two ships At noon, ship A was 12 nautical miles due north of ship B. Ship A was sailing south at 12 knots (naut

frozen [14]

Answer:

a) $\sqrt{144-288t+208t^2}$ b.) -12knots, 8 knots c) No e) $4\sqrt{13}$

Step-by-step explanation:

We know that the initial distance between ships A and B was 12 nautical miles. Ship A moves at 12 knots(nautical miles per hour) south. Ship B moves at 8 knots east.

We know that at time t , the ship A has moved $12\dot t (n.m)$ and ship B has moved $8\dot t (n.m)$ . We also know that the ship A moves closer to the line of the movement of B and that ship B moves further on its line.

Using Pythagorean theorem, we can write the distance s as:

$\sqrt{(12-12\dot t)^2 + (8\dot t)^2}\\s=\sqrt{144-288t+144t^2+64t^2}\\s=\sqrt{144-288t+208t^2}$

We want to find $\frac{ds}{dt}$ for t=0 and t=1

$\sqrt{144-288t+208t^2}|\frac{d}{dt}\\\\\frac{ds}{dt}=\frac{1}{2\sqrt{144-288t+208t^2}}\dot (-288+416t)\\\\\frac{ds}{dt}=\frac{208t-144}{\sqrt{144-288t+208t^2}}\\\\\frac{ds}{dt}(0)=\frac{208\dot 0-144}{\sqrt{144-288\dot 0 + 209\dot 0^2}}=-12knots\\\\\frac{ds}{dt}(1)=\frac{208\dot 1-144}{\sqrt{144-288\dot 1 + 209\dot 1^2}}=8knots$

We know that the visibility was 5n.m. We want to see whether the distance s was under 5 miles at any point.

Ships have seen each other = $s\leq 5\\\\\sqrt{144-288t+208t^2}\leq 5\\\\144-288t+208t^2\leq 25\\\\199-288t+208t^2\leq 0$

Since function $f(x)=199-288x+208x^2$ is quadratic, concave up and has no real roots, we know that $199-288x+208x^2>0$ for every t. So, the ships haven't seen each other.

Attachedis the graph of s(red) and ds/dt(blue). We can see that our results from parts b and c were correct.

Function ds/dt has a horizontal asympote in the first quadrant if

$\lim_{t \to \infty} \frac{ds}{dt}$

So, lets check this limit:

$\lim_{t \to \infty} \frac{ds}{dt}=\lim_{t \to \infty} \frac{208t-144}{\sqrt{144-288t+208t^2}}\\\\=\lim_{t \to \infty} \frac{208-\frac{144}{t}}{\sqrt{\frac{144}{t^2}-\frac{288}{t}+208}}\\\\=\frac{208-0}{\sqrt{0-0+208}}\\\\=\frac{208}{\sqrt{208}}\\\\=4\sqrt{13}$

Notice that:

$4\sqrt{13}=\sqrt{12^2+5^2}$ =√(speed of ship A² + speed of ship B²)

5 0

3 years ago