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Kobotan [32]
3 years ago
15

A fair dice is rolled 6 times. What is the probability of having no 2 and no 3 among the rolls? Round your answer to three decim

al places.
Mathematics
1 answer:
Ede4ka [16]3 years ago
4 0

Answer:

64/729

or 0.088 to 3 decimal places.

Step-by-step explanation:

The probability of no 2 and no 3 on one throw of the dices = 4/6 = 2/3.

For 6 rolls we multiply this 6 times because each throw is independent.

The answer is (2/3)^6

=  64/729

or 0.088 to 3 decimal places.

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