3 years ago

Three rays can share a common vertex. True or False?

Mathematics

1 answer:

Sliva [168]3 years ago

8 0

Yes, three rays can share a common vertex!

^o^

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51 is 33 1/3 of what number?

nevsk [136]

Answer:

$\boxed{\frac{153}{100}\:\:Or\:\:1.53}$

Step-by-step explanation:

Let the number be $n$ .

Then,

$33\frac{1}{3} \tmes n=51$

This implies that;

$\frac{100}{3} n=51$

We multiply both sides by $\frac{3}{100}$ to obtain;

$\frac{3}{100} \times \frac{100}{3}n=\frac{3}{100} \times 51$

$\Rightarrow n=\frac{3}{100} \times 51$

$\Rightarrow n=\frac{153}{100}$

$\Rightarrow n=1.53$

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3 years ago

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Bingel [31]

Answer:

:;;;,,,

Step-by-step explanation:

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2 years ago

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Please help reflect the point (-2,-3) and reflect it over the y-axis

Nesterboy [21]

Answer:

Step-by-step explanation:

use formula

A(x,y)=A'(-x,y)

(-2,-3)=(2,-3)

4 0

3 years ago

11. |6- 15| - |5(-4)|= ? A.-29 B. -11 C. 1 D. 11 E. 29

Burka [1]

Answer:

Step-by-step explanation:

|6- 15| - |5(-4)| =

|-9| - |-20| =

(9)- (20) =

-11

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2 years ago

At 2:00 pm there are 350 freshmen and 200 sophomores at a school carnival. After 2:00 pm 20 freshman leave every hour and 35 sop

dmitriy555 [2]

Answer:

160:340

Step-by-step explanation:

The hours between 2:00pm and 4:00pm is 2 hours. If originally 350 freshman and 200 sophomores are at the carnival, and 20 freshman leave every hour, we can determine how many freshman left in 2 hours:

$=20\cdot{2}=40$

and if 35 sophomores arrive every half our, we know that for every two hours there is 4 half hours, therefore:

$=35\cdot{4}=140$

The amount of freshman at 4:00pm:

$200-40=160$

and the amount of sophomores:

$200+140=340$

the ratio is 160:340

5 0

3 years ago

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