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Jet001 [13]
4 years ago
14

Three rays can share a common vertex. True or False?

Mathematics
1 answer:
Sliva [168]4 years ago
8 0
Yes, three rays can share a common vertex!

^o^
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Help for number 4 part a and part b
djyliett [7]
Part A:  7/10 because .7 represents 70/100 of a whole, or 7/10.

Part B: I think 1 and 89/100 because 89/100 represents that fraction

These are my answers, so I may be wrong.

Hope I helped, and good luck!

4 0
3 years ago
WILL MARK BRAINLIEST! NEED HELP!
Mice21 [21]

Answer:

The parent graph is translated 2 to the left and up 6 units.

Step-by-step explanation:

The +2 moves the  parent 2 units to the left and the + 6 moves it up 6 units.

4 0
3 years ago
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A man realizes he lost the detailed receipt from the store and only has the credit card receipt with the after-tax total. If the
Eva8 [605]
Heyyy hit me up if u want help.
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3 years ago
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Hi, I am taking PSAT and I am working on the math section. I need help with answering this math type of question. Please give th
ValentinkaMS [17]

By using the concept of uniform rectilinear motion, the distance surplus of the average race car is equal to 3 / 4 miles. (Right choice: A)

<h3>How many more distance does the average race car travels than the average consumer car?</h3>

In accordance with the statement, both the average consumer car and the average race car travel at constant speed (v), in miles per hour. The distance traveled by the vehicle (s), in miles, is equal to the product of the speed and time (t), in hours. The distance surplus (s'), in miles, done by the average race car is determined by the following expression:

s' = (v' - v) · t

Where:

  • v' - Speed of the average race car, in miles per hour.
  • v - Speed of the average consumer car, in miles per hour.
  • t - Time, in hours.

Please notice that a hour equal 3600 seconds. If we know that v' = 210 mi / h, v = 120 mi / h and t = 30 / 3600 h, then the distance surplus of the average race car is:

s' = (210 - 120) · (30 / 3600)

s' = 3 / 4 mi

The distance surplus of the average race car is equal to 3 / 4 miles.

To learn more on uniform rectilinear motion: brainly.com/question/10153269

#SPJ1

4 0
1 year ago
What is the area??????
Westkost [7]
Your answer would be 91.1 units².
We can split this shape into a trapezium and a semicircle, and then find the area of both and add them.
To find the area of a trapezium, the formula is
(a + b)/2 × h, which means we do 14 (the length of AD) + 8 (the length of BC) = 22, and 22/2 = 11. Then we multiply 11 by the height of the trapezium, which is 6 because 10 - 4 = 6. This gives us the area of the trapezium as 66 units².
To find the area of a semicircle, the formula is πr²/2, and the radius is 4 because the diameter is 8 (16 - 8 = 8). This means we do π4²/2 = 16π\2 = 8π = 25.13.
Then we need to add together 66 and 25.13, which equals 91.13, or 91.1 to the nearest tenth.
I hope this helps!
7 0
3 years ago
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