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4 years ago

If x varies directly as y and x= 18 when y =3 find x when y=7

Mathematics

1 answer:

denpristay [2]4 years ago

5 0

Answer:

Step-by-step explanation:

x = Ky

18 = K(3)

K = 18/3 = 6

x = 6y

x = 6(7) = 42

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How do I start this problem? I don't need help with the graphing part.

tamaranim1 [39]

Answer:

x = 6 , y = 0 (x , y) = (6 , 0)

x = 12, y = 3 (x , y) = (12 , 3)

x = 24, y = 9 (x , y) = (24 , 9)

Step-by-step explanation:

Simply plug in a x, and find a y that would make the equation true:

When x = 6:

6 - 2y = 6

6 (-6) - 2y = 6 (-6)

-2y = 0

(-2y)/-2 = (0)/-2

y = 0

When x = 6, y = 0 (x , y) = (6 , 0)

When x = 12:

12 - 2y = 6

12 (-12) -2y = 6 (-12)

-2y = -6

(-2y)/-2 = (-6)/-2

y = 3

When x = 12, y = 3 (x , y) = (12 , 3)

When x = 24:

24 - 2y = 6

24 (-24) - 2y = 6 (-24)

-2y = -18

(-2y)/-2 = (-18)/-2

y = 9

When x = 24, y = 9 (x , y) = (24 , 9)

3 0

3 years ago

40 pts PLEASE HELP ILL GIVE BRAINLIESTS A. -3 B. -1/3 C. 1/3 D. 3

Licemer1 [7]

<h3>A is the answer EEEE</h3>

5 0

3 years ago

Can someone help me with this please

larisa86 [58]

The correct answer is: [D]: " 576π cm³ " .

____________________________________________________

Explanation:

____________________________________________________

Use the formula for the volume, "V", of a cylinder, to find the volume of the given cylinder:

____________________________________________________

V = π r² h ;

in which:

V = volume (for which we shall solve).

π = π ; All the answer choices given are in terms of 'π' ;

r = radius = 6 cm (given);

h = height = 16 cm (given);

__________________________________________________________

Plug in these values into the formula to solve for the volume, "V" :

V = π r² h

= π * (6 cm)² * (16 cm) ;

= π * (6²) * (cm²) * (16 cm) ;

= π * (6*6) * 16 * cm³ ;

= π * (36) * 16 * cm³ ;

= π * (36 * 16) * cm³

___________________________________________________________

V = 576 π cm³ ; which is: Answer choice: [D]: " 576π cm³ " .

___________________________________________________________

4 0

3 years ago

A quadrilateral has vertices at A(–5, 5), B(1, 8), C(4, 2), D(–2, –2). Use slope to determine if the quadrilateral is a rectangl

lianna [129]

With the properties of rectangle in mind we must perform two verification. Verify to see if opposite sides are parallel and adjacent sides are perpendicular.

We need to determine the slope of each side, using the formula,

$m=\frac{y_2-y_1}{x_2-x_1 }$

Slope of AB

$m_{AB}=\frac{8-5}{1--5}$

$\Rightarrow m_{AB}=\frac{8-5}{1+5}$

$\Rightarrow m_{AB}=\frac{3}{6}$

$\Rightarrow m_{AB}=\frac{1}{2}$

Slope of BC

$m_{BC}=\frac{2-8}{4-1}$

$\Rightarrow m_{BC}=\frac{-6}{3}$

$\Rightarrow m_{BC}=-2$

Slope of CD

$m_{CD}=\frac{-2-2}{-2-4}$

$\Rightarrow m_{CD}=\frac{-2-2}{-2-4}$

$\Rightarrow m_{CD}=\frac{-4}{-6}$

$\Rightarrow m_{CD}=\frac{2}{3}$

Slope of AD

$m_{AD}=\frac{-2-5}{-2--5}$

$\Rightarrow m_{AD}=\frac{-2-5}{-2+5}$

$\Rightarrow m_{AD}=\frac{-7}{3}$

Verify Parallel sides

If the quadrilateral is a rectangle, then opposite sides should have the same slope. But

$m_{AD} = \frac{-7}{3} \neq m_{BC}=-2$

$m_{AB}=\frac{1}{2} \neq m_{CD}=\frac{2}{3}$

Verify Perpendicularity

And also the product of slopes of all sides with a common vertex should be -1. But

$m_{AB} \times m_{BC}=\frac{1}{2} \times -2=-1$

$m_{AB} \times m_{AD}=\frac{1}{2} \times -\frac{7}{3} \neq -1$

$\Rightarrow m_{CD} \times m_{AD}=\frac{2}{3} \times -\frac{7}{3} \neq -1$

$\Rightarrow m_{CD} \times m_{BC}=\frac{2}{3} \times -2 \neq -1$

Since the quadrilateral fails to satisfy all these conditions, the quadrilateral is not a rectangle

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3 years ago

Is the constant of proportionally in gallons per minute the same for every row? What does this say about the relationship of the

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Go slow to keep it down oil and water doesn’t mix

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3 years ago