8 21/40
341/40
852.5/100
8.525
Hope this helps :)
Let L and S represent the weights of large and small boxes, respectively. The problem statement gives rise to two equations:
.. 7L +9S = 273
.. 5L +3S = 141
You can solve these equations various ways. Using "elimination", we can multiply the second equation by 3 and subtract the first equation.
.. 3(5L +3S) -(7L +9S) = 3(141) -(273)
.. 8L = 150
.. L = 150/8 = 18.75
Then we can substitute into either equation to find S. Let's use the second one.
.. 5*18.75 +3S = 141
.. S = (141 -93.75)/3 = 15.75
A large box weighs 18.75 kg; a small box weighs 15.75 kg.
Answer:
I think the answer would be B.
Answer:
Step-by-step explanation:
A parabola has the following format:
If a is positive, it's minium value is:
In which
Factoring:
, in which 
are the intercepts.
In this question:
So
Suppose a = 1, we have:
The minimum value will be:
We want this minimum value to be -4, which is 4 times the current minimum value, so we need to multiply a by 4. Then
And the parabola is:
Then, Owen only uses one piece of the 4 yard ropes.
