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Stolb23 [73]
3 years ago
8

5(2y -6 ) + 5 = 2 (5y -15) +5

Mathematics
1 answer:
kicyunya [14]3 years ago
6 0

Answer: the answer is all real numbers

Step-by-step explanation: when you have this type of equation you would want to distribute 5 into 2 y and the -6 and 2 into 5y and -15

for more help just look up a calculator online

i noticed after a few steps you would get 10y on each side when i solved it. It gave me 0=0

there fore the numbers are equal

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The mean of this data set is 9. What number is missing?<br><br> 11,20,_,3,1
kherson [118]
Let the missing number be x

Mean is the total sum of data over the number of data therefore,

(11+20+x+3+1) / 5 = 9
Then simplify
(35 + x) / 5 = 9
Then multiply 5 to both sides
35 + x = 45
Then subtract 35 to both sides to find x
X= 10

Hope this helps!

7 0
2 years ago
A.42.6 square units<br> B. 128 square units <br> C. 32 square units <br> D. 64 square units
kirill [66]

Answer:

Step-by-step explanation:

D. 64 square units

4 0
3 years ago
Select all the expressions that are equivalent to 9 + 7x – 3y. 9 + 7x + 3y 9 – 7x – 3y 9 – 7x + 3y 9 + 7x + (–3y) 9 – (–7)x – 3y
bulgar [2K]

0^9 +7x+189yx−3y

o

9

+7x−3y

9

+7x+3y

9

−7x−3y

9

−7x+3y

9

+7x+189yx−3y

2 Collect like terms.

{o}^{9}+(7x+7x-7x-7x+7x)+(-3{y}^{9}+3{y}^{9}-3{y}^{9}+3{y}^{9})+189yx-3y

o

9

+(7x+7x−7x−7x+7x)+(−3y

9

+3y

9

−3y

9

+3y

9

)+189yx−3y

3 Simplify.

{o}^{9}+7x+189yx-3y

o

9

+7x+189yx−3y

6 0
2 years ago
two trains leave the station at the same time one heading west and the other East the westbound train travels at 55 miles per ho
Diano4ka-milaya [45]
Recall your d = rt, distance = rate * time

so... one train goes west and the goes the opposite way... alrite... so... notice, by the time 338 miles have been covered by both, it will have been "t" hours, and whatever "t" is, is the same amount of time the westbound train has been running as well as the eastbound train has been running.

now, let's say, since by "t" hours they've covered 338 altogether, so, if the westbound train has covered say "d" miles, then the eastbound train would have covered the slack from 338 and d, that is, "338 - d".

\bf \begin{array}{lccclll}&#10;&\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\&#10;&------&------&------\\&#10;Westbound&d&55&t\\&#10;Eastbound&338-d&75&t&#10;\end{array}&#10;\\\\\\&#10;\begin{cases}&#10;\boxed{d}=55t\\&#10;338-d=75t\\&#10;----------\\&#10;338-\boxed{55t}=75t&#10;\end{cases}&#10;\\\\\\&#10;338=75t+55t\implies 338=130t\implies \cfrac{338}{130}=t\implies \stackrel{hours}{2.6}=t

so, 2hours and 36 minutes.
8 0
3 years ago
(2<br> (4+4)<br> X2<br> Answer<br> No step by step explanation just the answer
DerKrebs [107]

Answer:

1

Step-by-step explanation:

I had brainliest but some kid reported me soooooo

6 0
3 years ago
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