Help please someone
2 answers:
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Answer:
.
Step-by-step explanation:
If a graph touches the x-axis at x=c, then (x-c) is a factor of function.
From the given graph it is clear that the graph of function intersect x-axis at x=1 and touch the x-axis at x=-2.
It means (x-1) and (x+2) are not factors of given function but power of (x+2) must be 2.
So, the required function is
...(1)
where, a is a constant.
From the given figure it is clear that the graph passes through the point (-4,-7). So, substitute x=-4 and f(x)=-7 in the above function.
Substitute in (1).
Therefore, the required function is .
Answer:
D
Step-by-step explanation:
From any point (x, y) on the parabola the focus and directrix are equidistant
Using the distance formula
= | y + 1 |
Squaring both sides
(x + 5)² + (y - 5)² = (y + 1)^2 , that is
(y + 1)² = (x + 5)² + (y - 5)² ← subtract (y - 5)² from both sides
(y + 1)² - (y - 5)² = (x + 5)² ← expand left side and simplify
y² + 2y + 1 - y² + 10y - 25 = (x + 5)²
12y - 24 = (x + 5)² ← factor left side
12(y - 2) = (x + 5)² ← divide both sides by 12
y - 2 = (x + 5)² ← add 2 to both sides
y = (x + 5)² + 2
or
f(x) = (x + 5)² + 2 → D