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Trava [24]
3 years ago
11

PLEASE ANY HELP IT POSSIBLE THANK YOU VERY MUCH ❤

Mathematics
1 answer:
yarga [219]3 years ago
3 0
The hight would be about 3.96

I just put the information given into the formula.

Then divided that by the given volume
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What is the perimeter of ABC to the nearest whole number?
kogti [31]

Answer:B

Step-by-step explanation: closes to caclation

8 0
3 years ago
A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
What’s the value of X and Y? (´⊙ω⊙`)
Crank
X is 11.
Y is 8.
°_°
:))))
6 0
4 years ago
Elena and Jada are 25 miles apart when they start moving toward each other. Elena runs at a constant speed of 6 mph and Jada wal
Setler [38]

<u>Answer:</u>

The Time taken by Elena and Jade  to meet up is 2.5 hours

<u>Explanation:</u>

Given,

Elena moves with a speed of 6mph  while Jada walks at a speed of 4 mph

Also, Distance can be calculated by the formula

Distance = Speed * Time

To find out the Total speed, i.e., speed of both Elena and Jada as both of them are walking in opposite direction we should add the speed of both the persons, if in same direction we should subtract the values  

Here it will be: 6 + 4 = 10mph

Distance apart is given as 25 miles. Substituting the values,

Distance = Speed * Time

25 = 10 * time

Time = 25/10

Time = 2.5 hour

Hence, It will take 2.5 hours to meet up.

3 0
4 years ago
Find the solution of the system of equations.<br> 10x+10y=40 <br> 5x+3y=8
ddd [48]

Answer:

x = -2 & y = 6

Step-by-step explanation:

10x+10y=40

10x+10y+ -10y=40+-10y

10x=-10y+40

\frac{10x}{10} =\frac{-10y+40}{10}

x=-y+4

5x+3y=8

5(-y+4)+3y=8

-2y+20=8

-2y+20+-20=8+-20

-2y=-12

\div2

y=6

x=-y+4

x=-6+4

x=-2

Hope this helps.

7 0
3 years ago
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