C(-8,2) and M(0,0) , since M is at the origin. Let x₁ and y₁ be the
coordinates of S →s(x₁ , y₁)
C(-8,2) and S(x₁ , y₁)
The coordinates of M, the midpoint of CS are M(x₂ , y₂)
a) x₂ = (-8 + x₁)/2 , but x₂ = 0, then :
0 = -4+x₁/2 and x₁ = 8
b) y₂ = (2+y₁)/2 , but y₂ = o, then:
0 = 2+ y₁/2 and y₂ = -2
Then the coordinates of S are S(8 , -2)
I need a question ok this is the a question
the answer would be 3 I believe
M = (y2 - y1)/(x2-x1)
= 2+5/-3-1
= 7/-4
= -7/4
Since the radius for either the quarter or the whole circle is the same the radius of the circle shall be divided into 4 parts
Please refer to the photograph to know more about the answer