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Taya2010 [7]
2 years ago
12

Combine the like terms to create an equivalent expressionwhat is 2 x - x + 8​

Mathematics
1 answer:
Novay_Z [31]2 years ago
7 0

Answer:

x + 8

Step-by-step explanation:

when theres just an x or any number there it is the same as 1x

2x - 1x = 1x / x

1x + 8 aka x + 8

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Six friends each use a $2.00 off coupon to buy themselves a movie ticket. They spend a total of 42. What is the price of one mov
attashe74 [19]

Answer:

5

Step-by-step explanation:

you would do 42 divided by 7 which is 6 then subtract 2 from 7 and you would get 5

5 0
3 years ago
The following data points represent the number of points scored by each player on the Wildcats basketball team last game. ______
scoundrel [369]

Answer:

4

Step-by-step explanation:

  • If you take the lowest half of the data (from the lower extreme to the median) and find the median of these numbers, that is called the lower quartile or quartile 1.
  • If you take the upper half of the data (from the upper extreme to the median) and find the median of these numbers, that is called the upper quartile or quartile 3.
  • The interquartile range is the difference between quartile 1 and quartile 3.

  • 4, 5, 6, 8, 9, 10, 11, 13
  • Median=8.5
  • Q1=6.5
  • Q3=10.5
  • 10.5-6.5=4

I also added my PowerPoint if you didn't get what I was saying.

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7 0
3 years ago
Questions 11, 13 and 14 on the sheet with working out.
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6 0
3 years ago
Let y(t) be the solution to y˙=3te−y satisfying y(0)=3 . (a) Use Euler's Method with time step h=0.2 to approximate y(0.2),y(0.4
OLEGan [10]

Answer:

  • y(0.2)=3, y(0.4)=3.005974448, y(0.6)=3.017852169, y(0.8)=3.035458382, and y(1.0)=3.058523645
  • The general solution is y=\ln \left(\frac{3t^2}{2}+e^3\right)
  • The error in the approximations to y(0.2), y(0.6), and y(1):

|y(0.2)-y_{1}|=0.002982771

|y(0.6)-y_{3}|=0.008677796

|y(1)-y_{5}|=0.013499859

Step-by-step explanation:

<em>Point a:</em>

The Euler's method states that:

y_{n+1}=y_n+h \cdot f \left(t_n, y_n \right) where t_{n+1}=t_n + h

We have that h=0.2, t_{0}=0, y_{0} =3, f(t,y)=3te^{-y}

  • We need to find y(0.2) for y'=3te^{-y}, when y(0)=3, h=0.2 using the Euler's method.

So you need to:

t_{1}=t_{0}+h=0+0.2=0.2

y\left(t_{1}\right)=y\left(0.2)=y_{1}=y_{0}+h \cdot f \left(t_{0}, y_{0} \right)=3+h \cdot f \left(0, 3 \right)=

=3 + 0.2 \cdot \left(0 \right)= 3

y(0.2)=3

  • We need to find y(0.4) for y'=3te^{-y}, when y(0)=3, h=0.2 using the Euler's method.

So you need to:

t_{2}=t_{1}+h=0.2+0.2=0.4

y\left(t_{2}\right)=y\left(0.4)=y_{2}=y_{1}+h \cdot f \left(t_{1}, y_{1} \right)=3+h \cdot f \left(0.2, 3 \right)=

=3 + 0.2 \cdot \left(0.02987224102)= 3.005974448

y(0.4)=3.005974448

The Euler's Method is detailed in the following table.

<em>Point b:</em>

To find the general solution of y'=3te^{-y} you need to:

Rewrite in the form of a first order separable ODE:

e^yy'\:=3t\\e^y\cdot \frac{dy}{dt} =3t\\e^y \:dy\:=3t\:dt

Integrate each side:

\int \:e^ydy=e^y+C

\int \:3t\:dt=\frac{3t^2}{2}+C

e^y+C=\frac{3t^2}{2}+C\\e^y=\frac{3t^2}{2}+C_{1}

We know the initial condition y(0) = 3, we are going to use it to find the value of C_{1}

e^3=\frac{3\left(0\right)^2}{2}+C_1\\C_1=e^3

So we have:

e^y=\frac{3t^2}{2}+e^3

Solving for <em>y</em> we get:

\ln \left(e^y\right)=\ln \left(\frac{3t^2}{2}+e^3\right)\\y\ln \left(e\right)=\ln \left(\frac{3t^2}{2}+e^3\right)\\y=\ln \left(\frac{3t^2}{2}+e^3\right)

<em>Point c:</em>

To compute the error in the approximations y(0.2), y(0.6), and y(1) you need to:

Find the values y(0.2), y(0.6), and y(1) using y=\ln \left(\frac{3t^2}{2}+e^3\right)

y(0.2)=\ln \left(\frac{3(0.2)^2}{2}+e^3\right)=3.002982771

y(0.6)=\ln \left(\frac{3(0.6)^2}{2}+e^3\right)=3.026529965

y(1)=\ln \left(\frac{3(1)^2}{2}+e^3\right)=3.072023504

Next, where y_{1}, y_{3}, \:and \:y_{5} are from the table.

|y(0.2)-y_{1}|=|3.002982771-3|=0.002982771

|y(0.6)-y_{3}|=|3.026529965-3.017852169|=0.008677796

|y(1)-y_{5}|=|3.072023504-3.058523645|=0.013499859

3 0
3 years ago
Which of the following is an example of the associative property?
Mariulka [41]
Hey there!

Let's look at this one answer at a time. 

2(5 - 3) = 10 - 6 would classify as the distributive property because 2 times 5 is 10 and 2 times negative 3 equals negative 6. 

-7 + (19 + 5) = (-7 + 19) + 5 would classify as an example of the associative property of equality because both sides of the equation simplify to equal the same number, 17.

11 + (6 + 8) = 11 + (28 + 6) is not a property of equality because it simplifies out to be 25 = 45 which is not true. 25 can never be equal to 45. It's no solution.

1/3 * 3 = 1 would be a great example of the inverse property of multiplication because one third is the reciprocal of three. In other words the equation could look like this:  1/3 * 3/1 = 3/3 = 1

Hope that helps! Thanks for using Brainly!
7 0
4 years ago
Read 2 more answers
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