Complete the solution of the equation. Find the value of y when x equals -10. 2x-9y=-38

Which of the following statements about UK and UL is true?

dedylja [7]

Answer:

B

Step-by-step explanation:

7 0

3 years ago

Given that a triangle has two sides of lengths 5 inches and 7 inches, which is a possible length of the third side?

victus00 [196]

Answer:

big poop face looking butt with a massive forehead poopy duck dipers

Step-by-step explanation:

↑∴↔↔⇔⇔³∛÷≈≤≥≥β⇵⊕⊕¬⊕⊕⊕⊕⊕⊕¬∪∪⊥∡∠°∞㏒㏑∡Ф⇒⇒√³π∫↓∵∴∴ $\lim_{n \to \infty} a_n \lim_{n \to \infty} a_n \neq \sqrt{x} x^{2} x^{2} \geq \geq \pi \frac{x}{y}$ and thats why it is big poop face looking butt with a massive forehead poopy duck dipers

3 0

4 years ago

3b-4/2 = c (solve for b)<br><br> please show work, thanks!

liq [111]

Answer:

Step-by-step explanation:

1. multiply both sides by 2

2. add 4 to both sides

3b=2c+4

3. divide both sides by 3

b= $\frac{2b+4}{3}$

6 0

4 years ago

What is the answer i need help 2*2+7+10*8-3=?

Ray Of Light [21]

Answer:

88

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Which function is the same as y = 3 cosine (2 (x startfraction pi over 2 endfraction)) minus 2? y = 3 sine (2 (x startfraction p

kirza4 [7]

The function which is same as the function y = 3cos(2(x +π/2)) -2 is: Option A: y= 3sin(2(x + π/4)) - 2

<h3>How to convert sine of an angle to some angle of cosine?</h3>

We can use the fact that:

$\sin(\theta) = \cos(\pi/2 - \theta)\\\sin(\theta + \pi/2) = -\cos(\theta)\\\cos(\theta + \pi/2) = \sin(\theta)$

to convert the sine to cosine.

<h3>Which trigonometric functions are positive in which quadrant?</h3>

In first quadrant (0 < θ < π/2), all six trigonometric functions are positive.
In second quadrant(π/2 < θ < π), only sin and cosec are positive.
In the third quadrant (π < θ < 3π/2), only tangent and cotangent are positive.
In fourth (3π/2 < θ < 2π = 0), only cos and sec are positive.

(this all positive negative refers to the fact that if you use given angle as input to these functions, then what sign will these functions will evaluate based on in which quadrant does the given angle lies.)

Here, the given function is:

$y= 3\cos(2(x + \pi/2)) - 2$

The options are:

$y= 3\sin(2(x + \pi/4)) - 2$
$y= -3\sin(2(x + \pi/4)) - 2$
$y= 3\cos(2(x + \pi/4)) - 2$
$y= -3\cos(2(x + \pi/2)) - 2$

Checking all the options one by one:

Option 1: $y= 3\sin(2(x + \pi/4)) - 2$

$y= 3\sin(2(x + \pi/4)) - 2\\y= 3\sin (2x + \pi/2) -2\\y = -3\cos(2x) -2\\y = 3\cos(2x + \pi) -2\\y = 3\cos(2(x+ \pi/2)) -2$

(the last second step was the use of the fact that cos flips its sign after pi radian increment in its input)
Thus, this option is same as the given function.

Option 2: $y= -3\sin(2(x + \pi/4)) - 2$

This option if would be true, then from option 1 and this option, we'd get:
$-3\sin(2(x + \pi/4)) - 2= -3\sin(2(x + \pi/4)) - 2\\2(3\sin(2(x + \pi/4))) = 0\\\sin(2(x + \pi/4) = 0$