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Marina86 [1]
4 years ago
8

49/6 into a mixed number

Mathematics
2 answers:
marin [14]4 years ago
5 0
The answer is 8 1/6, use 49÷6=8 1/6
mote1985 [20]4 years ago
4 0
49/6 into a mixed number would be 8 1/6. This is because you would see how many times 6 can go into 49. Since 6 times 8= 48, you subtract that from 49. You are left with one. You put the number you multiplied 6 by as the whole number and the leftover one over six. I hope this helps!
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What is the slope of the line perpendicular to a line that contains the points (-5,4) and (-2,4)
steposvetlana [31]

Answer:

the slope of the line is: 0

Step-by-step explanation:

4-4=0

-2-5= 3

7 0
3 years ago
Josh attempted 56 free throws during the basketball season. He made 57 of them. How many free throws did he make?
Scorpion4ik [409]

Answer:

He made approximately 32 free throws.

Step-by-step explanation:

Assuming that there's a typo in the question and that he made 57% of his attempted free throws, then we can solve it as shown below:

We can apply a rule of three in order to calculate the number of free throws he made. This is done as follows:

56 free throws -> 100%

x free throws -> 57%

56/x = 100/57

100*x = 57*56

x = 57*56/100 = 31.92

It can also be solved by transforming the percentage in a fraction such as 57% = 57/100 and then multiplying it by the total attempts.

free throws made = 56*57/100 = 31.92

He made approximately 32 free throws.

7 0
3 years ago
-17 + 5x = 5(x – 5) + 8<br><br>What is x? ​
Anvisha [2.4K]

Answer:

infinite solutions

Step-by-step explanation:

cancel both sides and you get infinite solutions

7 0
3 years ago
A larger number is five more than twice the smaller number their sum is 80 find the number
Oksana_A [137]

Answer:

L= 5+2s

Step-by-step explanation:

Let L = the larger # and S = the smaller #.

A large # is 5 more than twice a smaller #.....This gives Eq 1) L = 5 + 2S

Their sum is 80...This gives Eq 2) L + S = 80.

Substitute Eq 1) into Eq 2), you get

L + S = 80

5 + 2S + S = 80

L = 5 + 2S

 

3 0
4 years ago
Simplify each of the following powers of i. i^15
frutty [35]

Answer: -i

Step-by-step explanation:

You need to remember:

1. The Product of powers property: (a^m)(a^n)=a^{(m+n)}

2. The Power of a power property: (a^m)^n=a^{mn}

In this case, given:

i^{15}

You need to follow these steps in order to simplify it:

1. Apply the Product of powers property:

i^{15}=i^{12}i^2i

2. Apply the Power of a power property:

(i^{4})^3i^2i

3. Finally, since i^4=1 and i^2=-1, you get:

 =(1)(-1)(i)=-i

7 0
3 years ago
Read 2 more answers
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