<span>triangle ABD and the triangle CDB are similar
the options are </span><span>ASA and CPCTC</span>
The number of the students in the school that have had algebra is 203
<h3>How to determine the number of students?</h3>
The given parameters in the question are
- Proportion of students taking algebra, p = 70%
- Number of students in the school, n = 290
The number of students that had algebra in the school is calculated as:
Algebra = Proportion of students taking algebra * Number of students in the school
The above equation can be represented as:
Algebra = np
Substitute values for n and p in the above equation
So, we have
Algebra = 290 * 70%
Express 70% as decimal i.e. 0.70
So, we have
Algebra = 290 * 0.70
Evaluate the product i.e. multiply 290 and 0.70
So, we have
Algebra = 203
Hence, the number of the students in the school that have had algebra is 203
Read more about expected values at:
brainly.com/question/15858152
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The answer is 63 because you have set up the proportion 1.5 over 3 = 31.5 over x and then you cross multiply 31.5 times 3 and you get 94.5 then you divide that by 1.5 and you get 63.
The equation that represents the data on the table shown below is y = 38(1/2)^x
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