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soldier1979 [14.2K]
3 years ago
11

How long is the arc intersected by a 2pi/3 radian central angle in a circle with radius 7 feet?

Mathematics
2 answers:
VashaNatasha [74]3 years ago
4 0

=\frac{43.96}{3}Formula to find the central angle is,

s= r\theta

Where, s = arc length

r = radius

\theta= central angle in radian.

According to the given problem,

r = 7 and \theta = \frac{2\pi}{3}.

First step is to plug in these values in the above formula. So,

s= 7*\frac{2\pi}{3}

=\frac{14\pi}{3} By simplifying.

=\frac{14*3.14}{3} Since \pi =3.14

=\frac{14*3.14}{3}

s=14.65

Hence, arc length iss 14.65 feet.

dangina [55]3 years ago
3 0

Answer:

14π/3 feet

Step-by-step explanation:

The next answer is 2.36 and the next is 21.24

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In the diagram, TC represents a vertical building. The points, A and B, are on the same level as the foot C of the building such
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(a) The height of the building is 60.06 m

(b) The distance AB is 139.43 m

Step-by-step explanation:

The given parameters are

Given that segment BT = segment AT + 29

By trigonometric ratios, we have;

cos∠ATC = CT/AT

cos∠BTC = CT/BT

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cos(40°) = CT/AT.................................(1)

cos(56°) = CT/BT = CT/(AT + 29).....(2)

cos(56°) = CT/(AT + 29)......................(3)

From equation (1)

CT = AT×cos(40°)

From equation (3)

AT×cos(56°) + 29 × cos(56°) = CT

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AT×cos(40°) = AT×cos(56°) + 29 × cos(56°)

AT×cos(40°) - AT×cos(56°) =  29 × cos(56°)

AT×(cos(40°) - cos(56°)) =  29 × cos(56°)

AT = 29 × cos(56°)/(cos(40°) - cos(56°)) = 78.4 m

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The height of the building = 60.06 m

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The distance AB =  139.43 m.

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