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soldier1979 [14.2K]
3 years ago
11

How long is the arc intersected by a 2pi/3 radian central angle in a circle with radius 7 feet?

Mathematics
2 answers:
VashaNatasha [74]3 years ago
4 0

=\frac{43.96}{3}Formula to find the central angle is,

s= r\theta

Where, s = arc length

r = radius

\theta= central angle in radian.

According to the given problem,

r = 7 and \theta = \frac{2\pi}{3}.

First step is to plug in these values in the above formula. So,

s= 7*\frac{2\pi}{3}

=\frac{14\pi}{3} By simplifying.

=\frac{14*3.14}{3} Since \pi =3.14

=\frac{14*3.14}{3}

s=14.65

Hence, arc length iss 14.65 feet.

dangina [55]3 years ago
3 0

Answer:

14π/3 feet

Step-by-step explanation:

The next answer is 2.36 and the next is 21.24

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2 years ago
Given g(x)=x^2 and h(x)= x-3 find (g ∘ h)(x)
DerKrebs [107]

Answer:

<h2>(g ∘ h)(x) = x² - 6x + 9</h2>

Step-by-step explanation:

g(x) = x²

h(x) = x - 3

To find (g ∘ h)(x) substitute h(x) into g(x) that's for every x in g(x) replace it with h(x)

That's

(g ∘ h)(x) = ( x - 3)²

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We have the final answer as

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Hope this helps you

5 0
3 years ago
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This the correct answer

3 0
2 years ago
Solve for p. <br> −160=22+8(3p−4)
Aneli [31]
-160=22+8(3p-4)
Use distributive property
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Add 10 for both side
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Divided 24 for both side
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p=-6.25
Check:
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3 0
2 years ago
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ur 2 numbers are : 20 and 15
6 0
2 years ago
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