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2 years ago

Pythagorean theorem (picture provided)

Mathematics

2 answers:

const2013 [10]2 years ago

6 0

Answer:

Step-by-step explanation:

To solve for a side using pythag:

$\sqrt{37^2-35^2}$

kenny6666 [7]2 years ago

5 0

The answer would be 12

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State the domain of the following : a. y = √ x + 1 /√ 25 − x^2 b. f(x) = (√ 1 − x ) ln x

almond37 [142]

Answer:

a.) -1 < x < 5

b.) x <= 1

Step-by-step explanation: Domain is the independent variable (x).

For both question a and b, make sure that the number under the square root does not end up being negative. And the denominator of the fractional number is not equal to zero when variable x is being substituted for any value.

a.) y = √ x + 1 /√ 25 − x^2

Domain : -1 < x < 5

That is the minimum value for x is 0 and the maximum value is 4

b. f(x) = (√ 1 − x ) ln x

Domain : x <= 1

That is, x is less than or equal to 1

The maximum value for x is 1. x can be

1, 0, -1, -2, -3, ..........

8 0

2 years ago

The question is on the picture included

Alexxx [7]

The next step is to draw an arc with center E.

4 0

2 years ago

Use f(x) = 1 - 4x + 1). Find f(-5)

steposvetlana [31]

F(-5)=(1 - 4(-5) +1 )
=1+20+1
F(-5)=22

6 0

3 years ago

Read 2 more answers

Simplify. Y plus(15+ y) A.15y B.15+2y C.17y D.15+y

Arte-miy333 [17]

Answer:

2y+15

Step-by-step explanation:

y+(15+y)

y+15+y

(y+y)+15

2y+15

3 0

3 years ago

Read 2 more answers

The diameters of ball bearings are distributed normally. The mean diameter is 123 millimeters and the standard deviation is 4 mi

Mrac [35]

Answer:

0.0668

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 123, \sigma = 4$