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kirza4 [7]
3 years ago
12

Pythagorean theorem (picture provided)

Mathematics
2 answers:
const2013 [10]3 years ago
6 0

Answer:

12

Step-by-step explanation:

To solve for a side using pythag:

\sqrt{37^2-35^2}

kenny6666 [7]3 years ago
5 0
The answer would be 12
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Solve using Quadratic Formula <br>x^2 + 3x - 3 = 0​
katrin [286]

Answer:

a= 1 , b= 3 , c= –3

x =  \frac{ - b \frac{ + }{}  \sqrt{ {b}^{2}  - 4ac} }{2a}  \\ x =  \frac{ - 3  \frac{ + }{} {}  \sqrt{ {3}^{2}  - 4(1)( - 3)} }{2(1)}  \\  =   \frac{ - 3 \frac{ + }{}  \sqrt{9 + 12} }{2}  =  \frac{ - 3 \frac{ + }{} \sqrt{21}  }{2}  \\ \\  x =  \frac{ - 3 \frac{ + }{} \sqrt{21}  }{2}  \\  \\ x = 0.79 \\ x =  - 3.79

I hope I helped you^_^

4 0
3 years ago
Why do scientists use the international system of units (SI)
k0ka [10]
So it can be known anywhere. So we use all of the same measurements
7 0
3 years ago
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Evaluate the expression 40÷1+3-(3×7)+7-5
Eduardwww [97]
For this problem, you will have to use PEMDAS  (Parentheses) (Exponents) (Multiplication/Division) (Addition/Subtraction)

First of all, you will want to solve for the values inside the parentheses first

40 <span>÷ 1+3-(21)+7-5      Now check for anything that includes                                                                   multiplication/division and do that

40+3-21+7-5              All you have left now is addition and subtraction. It                                           must go from left to right, therefore if addition is first,                                       do addition, if subtraction is first, then do subtraction.

Final answer = 24</span>
8 0
3 years ago
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In microbiology, colony-forming units (CFUs) are used to measure the number of microorganisms present in a sample. To determine
zimovet [89]

Answer:

(a)  0.2650

(b)  0.0111

(c)  0.0105

(d)  0.0006

Step-by-step explanation:

Given that:

In microbiology, colony-forming units (CFUs) are used to measure the number of microorganisms present in a sample.

Suppose that the number of CFUs that appear after incubation follows a Poisson distribution with mean μ = 15.       &;

If the area of the agar plate is 75cm²;

what is the probability  of observing fewer than 4 CFUs in a 25 cm² area of the plate.

We can determine the mean number of CFUs that appear on a 25cm² area of the plate as follows;

75cm²/25cm² = 3

Since;

mean  μ = 15  

mean number of CFUs that appear on a 25cm² = 15/3 = 5 CFUs

Thus ; the probability of observing fewer than 4 CFUs in a 25 cm² area of the plate is estimated as:

= P(X < 4)

Using the EXCEL FUNCTION ( = poisson.dist(3, 5, TRUE) )

we have ;

P(X < 4) = 0.2650

b) If you were to count the total number of CFUs in 5 plates, what is the probability you would observe more than 95 CFUs?

Given that the total number of CFUs = 5 plates; then the mean number of CFUs in 5 plates =  15×5 = 75 CFUs

The probability is therefore = P( X > 95 )

= 1 - P(X ≤ 95)

= 1 - poisson.dist(95,75,TRUE) ( by using the excel function)

= 0.0111

c) Repeat the probability calculation in part (b) but now use the normal approximation.

Let assume that the mean and the variance of the poisson distribution are equal

Then;

X \sim N (\mu = 75 , \sigma^2 = 75)

We are to repeated the probability calculation in part (b) from above;

So:

P( X > 95 )

use the normal approximation

From standard normal variable table:

P(Z > 2.3094)

Using normal table

P(Z > 2.3094) = 0.0105

(d)  Find the difference between this value and your answer in part (b).

So;

the difference between the value in part c and part b is;

=  0.0111 - 0.0105

= 6*10^{-4}

= 0.0006 to four decimal places

5 0
3 years ago
WORTH 15 POINTS<br> ⚠️MAKE SURE TO USE SURDS ⚠️<br> ANSWER ASAP WILL GIVE BRAINLIEST
satela [25.4K]

Answer:

i got 1.23 don't think its right though so someone check me

Step-by-step explanation:

3 0
3 years ago
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