L ≥ 5w + 4
2(L+w) ≥ 32
L+w ≥ 16
6w + 4 ≥ 16
6w ≥ 12
w ≥ 2
L ≥ 5w + 4
L ≥ 14
If L = 14 and w = 2 then the perimeter is 32.
These are the smallest dimensions that fit the criteria.
Note: If we raise the width by 1 to w = 3
then the length is at least 19. At 19 by 3 we have P = 44
Like would be appreciated!!
D=s*t
distaance=speed times time
cd=coyote distance*time=ds*dt
rd=rabbit diatance*time=rs*rt
given
t=6 for all, so dt=rt=6
and ds=43
rs=35
cd=43*6=258miles
rd=35*6=210miles
how much more?
258-210=48
48 more miles
162.15 is the answer because you have to multiply 0.15•141 then add 21.15 to the 141 :)
