Question

3x + 1 over 4y2

Answer 1

Answer:

$\frac{5}{32}$

Step-by-step explanation:

given $\frac{3x+1}{y^{2} }$

substitute x = 3 and y = 4 into the expression

= $\frac{3(3)+1}{4(4)^{2} }$

= $\frac{9+1}{4(16)}$ = $\frac{10}{64}$ = $\frac{5}{32}$