The sides of the box are 12in by 12in by 30in.
The interior diagonal =[12^2+12^2+30^2]0.5
=[144+144+900]^0.5
=1188^0.5
The final answer is 34.47in.
My deepest apology if this is not what you meant.
= 34.47in.
Answer:
X = 2
Y = 1
Step-by-step explanation:
x + 4y = 6
3x + 3y = 9
3x + 12y = 18
3x + 3y = 9
9y = 9
x + 4y = 6
y = 1
x + 4 * 1 = 6
y = 1
x + 4 = 6
y = 1
x = 2
so there ia only 1 solution for this equation is (2;1)
Done :))
Answer:
173x^2+107x+24
Step-by-step explanation:
9x-x^2+7x+8+10x-x^2+19x+8-x^2+26x+88x^2+10x+88x^2+26x+8
173x^2+107x+24
Answer:
length = 60 foot, width = 30 foot
Step-by-step explanation:
Area of rectangular part, A = 1800 ft²
Cost of fencing three sides is $ 6 per foot and cost of one side fencing is $18 per foot.
Let the length of the rectangle is l and the width of the rectangle is W.
Area = Length x width
A = L x W
1800 = L x W ...... (1)
Total cost of fencing, C = 6 x ( L + W + L) + 18 x W
C = 6 (2L + W) + 18 W
C = 12 L + 24 W
Substitute the value of W from equation (1),
in equation (2)


Differentiate both sides with respect to L:

Put it equal to zero for maxima and minima

L = 60 foot
and W = 30 foot
So, the costing is minimum for length = 60 foot and the width = 30 foot.