Question

Bob's age is 4 times greater than Susan's. Dakota is 3 years younger than Susan. Some of Bob's, Susan's, and Dakota's age is 93. What is Susan's age?

Answer 1

Answer:

Therefore the age of Susan is 19.4 years.

Step-by-step explanation:

Given, the age of Bob is 4 times greater than the age of Susan.

It means Bob's age = 4×Susan's age........(1)

Again, the age of Dakota is 4 less than Susan.

It means Susan's age - 4=Dakota's age.......(2)

In (1) and (2)only Susan's age  is common.

So, Let the age of Susan be x.

From (1) we get

Bob's age = 4×x = 4x    [ Since Susan's age= x]

From (2) we get

Dakota's age= x-4

Again given that the sum of all three age is 93.

It means

Bob's age+Susan's age+Dakota's age= 93

Putting the age of the three

⇒4x+x+(x-4)=93

⇒4x+x+x-4=93

⇒5x=93+4

⇒5x=97

$\Rightarrow x=\frac{97}{5}$

⇒x = 19.4

Therefore the age of Susan is 19.4 years.