Question

A sculpture of a clothespin is 20 feet high. A normal clothespin of this shape is five inches high. Using this scale, how many feet tall would a sculpture of a 5-foot, 7-inch woman be?

Answer 1

Answer:

The sculpture of the woman must be 268 inches tall.

Step-by-step explanation:

This problem is about proportions and scales factors.

According to the problem, a sculpture of a clothespin is 20 feet, and a normal clothespin is 5 inches high.

So, the ratio is $\frac{20}{5}=4$

If a woman is 5 feet and 7 inches, the height of her sculpture must be in the given ratio.

First, we need to use only inches units. We know that 1 foot is 12 inches.

$5ft\frac{12in}{1ft} + 7=60+7=67in$

So, the woman height is 67 inches.

Using the given scale factor, we multiply it with the height of the woman

$67 \times 4 = 268 in$

Therefore, the sculpture of the woman must be 268 inches tall.

Answer 2

This is the concept of scale factor. The linear scale factor is given by:
(height of sculpture)/(height of clothespin)
=20/(5/12)
=48
Given that a woman is 5ft 7 in, the sculpture of this woman would be:
height of sculpture=(scale factor)*(height of the woman)
height of the woman=5 ft 7 inches=5 7/12 ft=67/12 ft
hence the height of the sculpture will be:
67/12×48
=268 ft

Answer: 268 ft