Step-by-step explanation:
6b < 42 or 4b + 12 > 8
6b < 42
= 6b/6 < 42/6
= b < 7
4b + 12 > 8
=4b - 12 + 12 < -12+8
= 4b > - 12 + 8
= 4b > -4
= 4b/4 = -4/4
b > -1
so
7 > b > -1
Answer:
![\frac{(a-b)^2+b^2}{a^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%28a-b%29%5E2%2Bb%5E2%7D%7Ba%5E2%7D)
Step-by-step explanation:
Since, By the given diagram,
The side of the inner square = Distance between the points (0,b) and (a-b,0)
![=\sqrt{(a-b-0)^2+(0-b)^2}](https://tex.z-dn.net/?f=%3D%5Csqrt%7B%28a-b-0%29%5E2%2B%280-b%29%5E2%7D)
![=\sqrt{(a-b)^2+b^2}](https://tex.z-dn.net/?f=%3D%5Csqrt%7B%28a-b%29%5E2%2Bb%5E2%7D)
Thus the area of the inner square = (side)²
![=(\sqrt{(a-b)^2+b^2})^2](https://tex.z-dn.net/?f=%3D%28%5Csqrt%7B%28a-b%29%5E2%2Bb%5E2%7D%29%5E2)
![=(a-b)^2+b^2\text{ square cm}](https://tex.z-dn.net/?f=%3D%28a-b%29%5E2%2Bb%5E2%5Ctext%7B%20square%20cm%7D)
Now, the side of the outer square = Distance between the points (0,0) and (a,0),
![=\sqrt{(a-0)^2+0^2}](https://tex.z-dn.net/?f=%3D%5Csqrt%7B%28a-0%29%5E2%2B0%5E2%7D)
![=\sqrt{a^2}=a](https://tex.z-dn.net/?f=%3D%5Csqrt%7Ba%5E2%7D%3Da)
Thus, the area of the outer square = (side)²
![=a^2\text{ square cm}](https://tex.z-dn.net/?f=%3Da%5E2%5Ctext%7B%20square%20cm%7D)
Hence, the ratio of the area of the inner square to the area of the outer square
![=\frac{(a-b)^2+b^2}{a^2}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%28a-b%29%5E2%2Bb%5E2%7D%7Ba%5E2%7D)
Answer:
Can you please give a clearer explanation of what is your question?
Step-by-step explanation:
4.5 divided by 1.25 is 3.6
for peices in total it is 4.
for peices the right length it is 3