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german
3 years ago
14

I need help quickly with these problems please see the images thank you so much

Mathematics
1 answer:
Ugo [173]3 years ago
3 0
By law of the sine we have:
 sine (y) /35.2=sine (95) / 86
 Clearing we have:
 sine (y) = (sine (95) / 86) * (35.2)
 y = asine ((sine (95) / 86) * (35.2))
 y = 24.0632456
 Rounding:
 y = 24 degrees
 Answer:
 
The answer for this case is given by:
 
y = 24 degrees
 
option 1
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Shauna spent $175 on a pair of shoes.She spent 1/9 of the remaining money on a shirt.If he still had 4/7of his moneyleft,how muc
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Answer:

$490

Step-by-step explanation:

Shauna spent $175 on a pair of shoes.

She spent 1/9 of the remaining money on a shirt.

If he still had 4/7 of his money left,how much did he have at first ?

Solution:

Let at first, Shauna have = x

Money spent on a pair of shoes = $175

Remaining money = x-175

<u>As she spent 1/9 of the remaining money on a shirt.</u>

Money spent on shirt = \frac{1}{9} \times(x-175)=\frac{x}{9} -\frac{175}{9}

As he still had \frac{4}{7} of his money left:-

Money left = \frac{4}{7}\ of\ his\ money=\frac{4x}{7}

Money left with Shauna = Total money, she had at first -(Money spent on a pair of shoes + Money spent on shirt )

\frac{4x}{7} =x-(175+{\frac{x}{9} -\frac{175}{9} )\\\\\\

\frac{4x}{7} =x-(\frac{175}{1} -\frac{175}{9} +\frac{x}{9} )\\\\ \frac{4x}{7} =x-(\frac{1575-175}{9} +\frac{x}{9} )\\\\ \frac{4x}{7}=x-(\frac{1400}{9} +\frac{x}{9} )\\ \\ \frac{4x}{7}=x-\frac{1400}{9} -\frac{x}{9}

Subtracting both sides by x and adding both sides by \frac{x}{9}

\frac{4x}{7} -x+\frac{x}{9} =-\frac{1400}{9} -x+\frac{x}{9} +x-\frac{x}{9}

Taking LCM of 7 and 9, we get 63

\frac{36x-63x+7x}{63} =-\frac{1400}{9} \\ \\ -\frac{20x}{63}=-\frac{1400}{9}

Adding both side by -

\frac{36x-63x+7x}{63} =-\frac{1400}{9} \\ \\ \frac{20x}{63}=\frac{1400}{9}

By cross multiplication:

20x\times9=1400\times63\\180x=88200\\

Dividing both sides by 180

x=490

Therefore, total $490, she had at first.

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