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3 years ago

What is the value of n in the equation 3n + 2(n + 2) = 9n + 12? −4 −2 2 4

Mathematics

1 answer:

Svet_ta [14]3 years ago

3 0

Answer:

-2

Step-by-step explanation:

3n+2n+4=9n+12

5n+4=9n+12

5n-9n=-4+12

-4n=8

n=8/-4

n= -2

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Two angles are complementary. The first angle is 2x degrees. The second angle is (3x +5) degrees. Determine the measure of each

bixtya [17]

Answer:

70 and 110

Step-by-step explanation:

First angle -- 2x

Second angle -- 3x + 5

Therefore,

2x + 3x + 5 = 180

5x = 175

x = 35

Therefore, 2x -- 70

3x + 5 -------------110

Thenks and mark me brainliest :)

8 0

3 years ago

Simplify using order of operations 12-36 divided by 9

tiny-mole [99]

Answer:

Step-by-step explanation:

36/9=4

12-4=8

8 is your answer

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2 years ago

Ann, Ben, and Cindy were eating strawberries. The ratio of the numbers of berries they ate is 5:5:7. If Cindy ate 30 strawberrie

agasfer [191]

Answer:

170

Step-by-step explanation:

Ann, Ben, and Cindy were eating strawberries.

The ratio of the numbers of berries they ate is 5:5:7.

If Cindy ate 30 strawberries less than Ann and Ben together,

find:

what is the total number of strawberries the three of them ate?

solution:

add the ratios 5 + 5 + 7 = 17

since Cindy ate 30, less than Ann and Ben together so, the equation is

7x = 5x + 5x - 30

7x - 10x = -30

x = 30/3

x = 10

ann 5 x 10 = 50

ben 5 x 10 = 50

cindy 7 x 10 = 70

total = 170

7 0

3 years ago

Find \tan\left(\frac{17\pi}{12}\right)tan( 12 17π )tangent, left parenthesis, start fraction, 17, pi, divided by, 12, end frac

uranmaximum [27]

One way to do this is to notice

$\dfrac{17\pi}{12}=\dfrac\pi6+\dfrac{5\pi}4$

Then

$\tan\dfrac{17\pi}{12}=\tan\left(\dfrac\pi6+\dfrac{5\pi}4\right)=\dfrac{\tan\frac\pi6+\tan\frac{5\pi}4}{1-\tan\frac\pi6\tan\frac{5\pi}4}$

We have

$\tan\dfrac\pi6=\dfrac{\sin\frac\pi6}{\cos\frac\pi6}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}$

and since $\tan x$ has a period of $\pi$ ,

$\tan\dfrac{5\pi}4=\tan\left(\pi+\dfrac\pi4\right)=\tan\dfrac\pi4=1$

and so

$\tan\dfrac{17\pi}{12}=\dfrac{\frac1{\sqrt3}+1}{1-\frac1{\sqrt3}}=\dfrac{1+\sqrt3}{\sqrt3-1}=2+\sqrt3$

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3 years ago

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andreev551 [17]

Answer:

-3<n<=5

Step-by-step explanation:

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4 0

3 years ago