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dem82 [27]
2 years ago
14

Chris buys 8 more Ninja Turtles than Star Wars action figures. The Ninja Turtles cost $7 each and the Star Wars cost $9 each. Wr

ite an expression to model this situation, using S for Star Wars.
Mathematics
1 answer:
Natalka [10]2 years ago
4 0

Answer:

Total Cost, C=$(16S +56)

Step-by-step explanation:

Chris buys 8 more Ninja Turtles than Star Wars action figures.

Cost of each Ninja Turtle = $7

Cost of each Star Wars  = $9

Let number of Star Wars bought = S

As per question statement, number of Ninja Turtles bought = S+8

Cost of 'S' number of Star Wars = Number of Star Wars bought \times cost of each Star Wars

Total cost of Star Wars bought = S \times 9 or $9S

Similarly, Cost of 'S+8' number of Ninja Turtles = Number of Ninja Turtles bought \times cost of each Ninja Turtles

Total cost of Ninja Turtles bought = (S+8) \times 7 or $(7S +56)

Total Cost of the purchase = Total cost of Star Wars Bought + Total cost of Ninja Turtles bought

Total Cost of the purchase, C = 9S + (7S +56)

\Rightarrow C=\$(16S +56)

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PLEASE HELP! I WILL GIVE BRAINLYEST TO WHOEVER ANSWERS FIRST! PLEASE PLEASE BE QUICK! thank you! and please include explanation
katrin2010 [14]

Answer:

A=920 ft.

Step-by-step explanation:

Using the formulas

A=2AB+(a+b+c)h

AB=s(s﹣a)(s﹣b)(s﹣c)

s=a+b+c

2

Solving for A

A=ah+bh+ch+1

2﹣a4+2(ab)2+2(ac)2﹣b4+2(bc)2﹣c4=8·20+17·20+15·20+1

2·﹣84+2·(8·17)2+2·(8·15)2﹣174+2·(17·15)2﹣154=920

4 0
2 years ago
Let u and v be the solutions to 3x^2 + 5x + 7 = 0. Find u/v+v/u
Hitman42 [59]

Answer:   \dfrac{-17}{21}

Step-by-step explanation:

Given: u and v be are the solutions of  3x^2+5x+7=0

Let  ax^2+bx+c=0 is the quadratic equation and u and v are the zeroes/solutions then

Sum of zeroes;   u+v = \dfrac{-b}{a}

Product of zeroes; uv= \dfrac{c}{a}

Comparing  3x^2+5x+7=0  to  ax^2+bx+c=0

we get a= 3 , b= 5 and c = 7

u+v = \dfrac{-b}{a} = \dfrac{-5}{3}----(i)

uv= \dfrac{c}{a} = \dfrac{7}{3}----(ii)

Now we have to find

\dfrac{u}{v} +\dfrac{v}{u} =\dfrac{u^2+v^2}{uv} adding and subtracting 2uv in numerator we get

= \dfrac{u^2+v^2+2uv-2uv}{uv}= \dfrac{(u+v)^2-2uv}{uv}

Substituting the values from (i) and (ii) we get

\dfrac{(\dfrac{-5}{3} )^2-2\times \dfrac{7}{3} }{\dfrac{7}{3} } = \dfrac{\dfrac{25}{9} -\dfrac{14}{3} }{\dfrac{7}{3} }= \dfrac{\dfrac{25-42}{9} }{\dfrac{7}{3}} =\dfrac{-17}{9} \times \dfrac{3}{7} = \dfrac{-17}{21}

Hence, the value of \dfrac{u}{v} +\dfrac{v}{u}   is  \dfrac{-17}{21}

5 0
3 years ago
Help me out please help me​
Paul [167]
5x-22=3x+10
2x-22=10
2x=32
X=16
7 0
3 years ago
Are s^2 ,2s^2 and 3s^2 equivalent
alexira [117]
No they are not quivalent
5 0
3 years ago
Can someone explain how you do this and not only give me a answer?
german
You plug in 2 for the w and do 17 minus 2 and then you divide that by 3 so ur answer is going to be 17-2 which is 15 and then divide 15 by 3 and you get 5
7 0
3 years ago
Read 2 more answers
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