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3 years ago

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Chris buys 8 more Ninja Turtles than Star Wars action figures. The Ninja Turtles cost $7 each and the Star Wars cost $9 each. Wr

ite an expression to model this situation, using S for Star Wars.

1 answer:

Natalka [10]3 years ago

4 0

Answer:

Total Cost, C=$(16S +56)

Step-by-step explanation:

Chris buys 8 more Ninja Turtles than Star Wars action figures.

Cost of each Ninja Turtle = $7

Cost of each Star Wars = $9

Let number of Star Wars bought = S

As per question statement, number of Ninja Turtles bought = S+8

Cost of 'S' number of Star Wars = Number of Star Wars bought $\times$ cost of each Star Wars

Total cost of Star Wars bought = S $\times$ 9 or $9S

Similarly, Cost of 'S+8' number of Ninja Turtles = Number of Ninja Turtles bought $\times$ cost of each Ninja Turtles

Total cost of Ninja Turtles bought = (S+8) $\times$ 7 or $(7S +56)

Total Cost of the purchase = Total cost of Star Wars Bought + Total cost of Ninja Turtles bought

Total Cost of the purchase, C = 9S + (7S +56)

$\Rightarrow C=\$(16S +56)$

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Halla la tasa de variación de cada funcion en el intervalo [-4,3] e indica si es positiva , negativa o nula A) f(x)=x2-2x+4 B) f

masya89 [10]

Answer:

$A) \hspace{3}Rate\hspace{3}of\hspace{3}change=-5\hspace{3}Negative\\\\B)\hspace{3}Rate\hspace{3}of\hspace{3}change=-21\hspace{3}Negative$

Step-by-step explanation:

Given a function $f(x)$ , we called the rate of change to the number that represents the increase or decrease that the function experiences when increasing the independent variable from one value " $x_1$ " to another " $x_2$ ".

The rate of change of $f(x)$ between $x_1$ and $x_2$ can be calculated as follows:

$Rate\hspace{3}of\hspace{3}change=f(x_2)-f(x_1)$

For:

$f(x)=x^2-2x+4$

Let's find $f(x_1)$ and $f(x_2)$ , where:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=(-4)^2-2(4)+4=16-8+4=12\\f(x_2)=f(3)=(3)^2-2(3)+4=9-6+4=7$

So:

$Rate\hspace{3}of\hspace{3}change =7-12=-5\hspace{3}Negative$

And for:

$f(x)-3x+2$

Let's find $f(x_1)$ and $f(x_2)$ , where:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7$

So:

$Rate\hspace{3}of\hspace{3}change =-7-14=-21\hspace{3}Negative$

<em>Translation:</em>

Dada una función $f(x)$ , llamábamos tasa de variación al número que representa el aumento o disminución que experimenta la función al aumentar la variable independiente de un valor " $x_1$ " a otro " $x_2$ ".

La tasa de variación de $f(x)$ entre $x_1$ y $x_2$ , puede ser calculada de la siguiente forma:

$Tasa\hspace{3}de\hspace{3}variacion=f(x_2)-f(x_1)$

Para:

$f(x)=x^2-2x+4$

Encontremos $f(x_1)$ y $f(x_2)$ , donde:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7$

Entonces:

$Tasa\hspace{3}de\hspace{3}variacion =7-12=-5\hspace{3}Negativa$

Y para:

$f(x)-3x+2$

Encontremos $f(x_1)$ y $f(x_2)$ , donde:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7$

Entonces:

$Tasa\hspace{3}de\hspace{3}variacion=-7-14=-21\hspace{3}Negativa$

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4 years ago

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pishuonlain [190]

Answer:

Hello! if Chris garden is a square shape then the answer is 40 7/10 in fraction form or 40.7 in decimal form

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3 years ago

If you have a demand function of Qd=48-9P and a supply function of Qs=-12+6P,

jenyasd209 [6]

Answer:

The equilibrium quantity is 26.4

Step-by-step explanation:

Given

$Q_d = 48 - 9P$

$Q_s = 12 + 6P$

Required

Determine the equilibrium quantity

First, we need to determine the equilibrium by equating Qd to Qs

i.e.

$Q_d = Q_s$

This gives:

$48 -9P = 12 + 6P$

Collect Like Terms

$-9P - 6P = 12 - 48$

$-15P = -36$

Solve for P

$P = \frac{-36}{-15}$

$P =2.4$

This is the equilibrium price.

Substitute 2.4 for P in any of the quantity functions to give the equilibrium quantity:

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$Q_d = 48 - 9 * 2.4$

$Q_d = 26.4$

<em>Hence, the equilibrium quantity is 26.4</em>

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Ulleksa [173]

Answer:

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When Y=0

X+0=5

X=5

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When X=0

0-Y=3

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When Y=0

X-0=3

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when X=0

0+Y=7

Y=7

when Y=0

2x+0=7

2x=7

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(Iv)

3X-2Y=0

when X=0

0-2Y=0

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3x-0=0

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Answer:

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Step-by-step explanation:

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