We can employ a simple repeated decimal trick:



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Alternatively, we can compute the partial sum of the series.





As
, the second term vanishes and we're left with
. Notice that this is really just a more formal version of the earlier trick.
<span>She needs to save an additional 108 quarters.</span>
Answer:
isiiqywyysyu the first one the first time in a even if it well y eh I just saw your message garako thiya na na hey I k h I just got home from a ko xa ki xaina the morning to get well soon dd ko we
Step-by-step explanation:
- eheuieiriieu to be ei ufuirijwjjeuuwuw to jnndhejfjit
Fix you some claculations?