Answer:
Area = 32/3
Step-by-step explanation:
x = u
²
y = uv
z = 12v
²
0 ≤ u ≤ 2
0 ≤ v ≤ 1
Since ru = <2u, v, 0> and rv = <0, u, 24v>, we have
Where ru is the differentiation of x, y, z with respect to u and rv is the differentiation of x, y, z wit respect to v.
we find the cross product of ru and rv
ru × rv = 24v²i - 48uv²j + 2u²k
absolute value of ru × rv = 2u² + 24v²
We can now find the area
∫₀² du ∫₀¹ dv (2u² + 24v²) = ∫₀² du [2u²v + 8v³]₀¹ = 32/3
Detailed description can be found in the attachment
8 is your answe have a nice day
Answer = 0.5
hope this helps
Answer:
Option A, p
Step-by-step explanation:
<u>Step 1: Identify the correct answer
</u>
Since the value of the higher point is (6, 5). This means that the x-value or p is greater than q since the x-value will stay the same as 6. While the q value will become even smaller.
Answer: Option A, p
Answer:
3.1% increase
Step-by-step explanation:
Diameter1=25cm
Radius1=12.5cm
Circumference1=2x22/7x12.5
Diameter2=25.8cm
Radius2=12.9cm
Circumference2=2x22/7x12.9
% increase =Circumference2-Circumference1/Circumference2 x 100%= 2x22/7x12.9-2x22/7x12.5 / 2x22/7x12.9 x100%
12.9-12.5/12.9 x 100%
0.4/12.9 x 100%
4/129 x 100%
3.1%
