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2 years ago

6

A 6am one morning the temperature was -14 degrees by noon it rose 8 degrees and then rose another 2 degrees by 3pm. By 6pm the t

emperature had dropped 5 degrees. What was the temperature at 6pm

1 answer:

valentina_108 [34]2 years ago

3 0

Answer:

-9 degrees

Step-by-step explanation:

-14 + 8 = -6

-6 + 2 = -4

-4 - 5 = -9

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13. This is really hard. Help if you can. See image below.

Alik [6]

Answer:

all it is is L*w*h

Step-by-step explanation:

how to solf A) is 5*4*10 thats it and the same for b-d

5 0

3 years ago

Please help and show all work so I can fully understand it, thanks.

seraphim [82]

Answer:

$\frac{1}{m-4}$

Step-by-step explanation:

$\frac{\frac{4m-5}{m^4 -7m^3 +12m^2}}{\frac{4m-5}{m^3 -3m^2}}$

Factor the equation:

$\frac{\frac{4m-5}{m^2(m^2 -7m+12)}}{\frac{4m-5}{m^2(m-3)}}$

$\frac{\frac{4m-5}{m^2(m-3)(m-4)}}{\frac{4m-5}{m^2(m-3)}}$

Rewrite to suit the format of multiplying two fractions. Remember, dividing two fractions is the same as multiplying the first fraction by the reciprocal of the second. A reciprocal of a fraction is when one switches the place of the numerator and the denominator, that is, the value on top (numerator), and the value on the bottom (denominator).

$\frac{4m-5}{m^2(m-3)(m-4)}*\frac{m^2(m-3)}{4m-5}$

Simplify, take out common terms that are found on both the numerator and denominator

$\frac{4m-5}{m^2(m-3)(m-4)}*\frac{m^2(m-3)}{4m-5}$

$\frac{1}{m-4}$

4 0

3 years ago

Solve the inequality 4t^2 ≤ 9t-2 please show steps and interval notation. thank you!

Misha Larkins [42]

Answer:

[0.25, 2]

Step-by-step explanation:

We have

4t² ≤ 9t-2

subtract 9t-2 from both sides to make this a quadratic

4t²-9t+2 ≤ 0

To solve this, we can solve for 4t²-9t+2=0 and do some guess and check to find which values result in the function being less than 0.

4t²-9t+2=0

We can see that -8 and -1 add up to -9, the coefficient of t, and 4 (the coefficient of t²) and 2 multiply to 8, which is also equal to -8 * -1. Therefore, we can write this as

4t²-8t-t+2=0

4t(t-2)-1(t-2)=0

(4t-1)(t-2)=0

Our zeros are thus t=2 and t = 1/4. Using these zeros, we can set up three zones: t < 1/4, 1/4<t<2, and t>2. We can take one random value from each of these zones and see if it fits the criteria of

4t²-9t+2 ≤ 0

For t<1/4, we can plug in 0. 4(0)²-9(0) + 2 = 2 >0 , so this is not correct

For 1/4<t<2, we can plug 1 in. 4(1)²-9(1) +2 = -3 <0, so this is correct

For t > 2, we can plug 5 in. 4(5)²-9(5) + 2 = 57 > 0, so this is not correct.

Therefore, for 4t^2 ≤ 9t-2 , which can also be written as 4t²-9t+2 ≤ 0, when t is between 1/4 and 2, the inequality is correct. Furthermore, as the sides are equal when t= 1/4 and t=2, this can be written as [0.25, 2]

8 0

3 years ago

The original price of a car is 18,000, and it depreciates by 15% each year. What is the value of the car after three years?

Rashid [163]

Answer: $9,900

Step-by-step explanation:

Convert the percentage into a decimal: 0.15

Multiply 0.15 by 18000

The product is 2700

Multiply 2700 by the 3 years

The product is 8100

Subtract 8100 from 18000

The result is $9,900

3 0

3 years ago

What is ten times greater than 563,626

denpristay [2]

Answer: 5,636,260. Just add a zero behind and it's done! :)

6 0

3 years ago

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