SOMEONE PLEASE HELP ME ASAP!!!!!!!

he books in a private library are classified as fiction and nonfiction. There are 400 books in the library. There are 40 more fi

vfiekz [6]

First, you have to set a system of equations to determine the number of fiction and of nonfiction books.Call f the number of fiction books and n the number of nonfiction books. Then 400 = f + n. And f = n + 40 => n = f - 40 => 400 = f + f - 40 => 400 - 40 = 2f => f = 360 / 2 = 180. Now to find the probability of picking two fiction books, take into account the the Audrey will pick from 180 fiction books out of 400, and Ryan will pick from 179 fiction books out of 399, so the probability will be (180/ 400) * (179/399) = 0.20 (rounded to two decimals). Answer: 0.20

3 0

3 years ago

1/6m=5/8 i can't slove this question 8th Grade Math

murzikaleks [220]

we are given

$\frac{1}{6} m=\frac{5}{8}$

Since, we have to solve for m

so, we will try to isolate m on anyone side

so, firstly , we will get rid of 1/6

so, we can multiply both sides by 6

$6*\frac{1}{6} m=6*\frac{5}{8}$

$m=6*\frac{5}{8}$

now, we can simplify right side

$m=3*\frac{5}{4}$

now, we can multiply them

and we get

$m=\frac{15}{4}$ ...........Answer

4 0

2 years ago

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Please help me with those question please help with out number 1

alina1380 [7]

Answer:

1) For each value of x, a value of y is increased by 5.

x = 0, y = 5

x = 1, y = 10

x = 2, y = 15

x = 3, y = 20

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2) For each two values of x, a value of y is increased by 10.

x = 0, y = -2

x = 2, y = 8

x = 4, y = 18

x = 6, y = 28

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3)

x = 0, y = 1

x = 1, y = $\frac{7}{5}$

x = 5, y = 3

x = 10, y = 5

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4)

x = 0, y = 2

x = 1, y = 17

x = 2, y = 32

x = 5, y = 77

Step-by-step explanation:

This is as easy as replacing x for the actual value show on the table.

1)

$y=5x+5$

When x = 0, y = ?

$y=5(0)+5\\y=0+5\\y=5$

When x = 1, y = ?

$y=5(1)+5\\y=5+5\\y=10$

When x = 2, y = ?

$y=5(2)+5\\y=10+5\\y=15$

When x = 3, y = ?

$y=5(3)+5\\y=15+5\\y=20$

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2)

$y=5x-2$

When x = 0, y = ?

$y=5(0)-2\\y=0-2\\y=-2$

When x = 2, y = ?

$y=5(2)-2\\y=10-2\\y=8$

When x = 4, y = ?

$y=5(4)-2\\y=20-2\\y=18$

When x = 6, y = ?

$y=5(6)-2\\y=30-2\\y=28$

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3)

$y=\frac{2}{5}x +1$

When x = 0, y = ?

$y=\frac{2}{5}(0) +1$

$y=0 +1\\y=1$

When x = 1, y = ?

$y=\frac{2}{5}(1) +1\\y=\frac{2}{5} +1$

$y=\frac{2}{5}+1(\frac{5}{5})\\ y=\frac{2}{5}+\frac{5}{5} \\y=\frac{7}{5}$

When x = 5, y = ?

$y=\frac{2}{5}(5) +1\\y=2+1\\y=3$

When x = 10, y = ?

$y=\frac{2}{5}(10) +1\\y=2(2) +1\\y=4+1\\y=5$

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4)

$y=15x+2$

When x = 0, y = ?

$y=15(0)+2\\y=0+2\\y=2$

When x = 1, y = ?

$y=15(1)+2\\y=15+2\\y=17$

When x = 2, y = ?

$y=15(2)+2\\y=30+2\\y=32$

When x = 5, y = ?

$y=15(5)+2\\y=75+2\\y=77$

4 0

3 years ago

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Find x. I had been stuck on this one for awhile

Arlecino [84]

Answer:

34 degrees

Step-by-step explanation:

ok so 180-111=69

then the opposite angle from 37 is also 37

the the missing angle from the left triangle has to be 103

so then the angle below x is 77

and so we know x = 34 degrees

I hope that made sense.

4 0

2 years ago

1. The student government snack shop sold 32 items this week.

Anna35 [415]

fruit cup:8/32=

1/4=

25percent

veggie sticks:6/32=

3/16=

18.75percent

chips:14/32=

7/16=

43.75percent

water:4/32=

1/8=

12.5percent

5 0

2 years ago

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