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melisa1 [442]
4 years ago
9

The graph of the function g(x) = x2 + 3x - 4 is shifted 5 units to the left. Plot the zeros of the new function on the provided

graph. Drawing Tools Select Point ResetUndoDelete
Mathematics
1 answer:
jarptica [38.1K]4 years ago
7 0
Horizontal translations
 Suppose that h> 0
 To graph y = f (x + h), move the graph of h units to the left.
 We have then:
 g (x + 5) = (x + 5) 2 + 3 (x + 5) - 4
 Rewriting we have:
 f (x) = x ^ 2 + 10x + 25 + 3x + 15 - 4
 f (x) = x ^ 2 + 13x + 36
 Equaling zero we have:
 x ^ 2 + 13x + 36 = 0
 We look for the roots of the polynomial:
 (x + 9) (x + 4) = 0
 x1 = -9
 x2 = -4
 Answer:
 
The zeros of the new function are:
 
x1 = -9
 
x2 = -4
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In a rectangle FGHI, diagonals FH and GI intersect at E<br> What is the length of FH?
Hunter-Best [27]

Answer:

The length of \overline {FH} is;

D. 38 units

Step-by-step explanation:

The given parameters are;

The type of the given quadrilateral FGHI = Rectangle

The diagonals of the quadrilateral = \overline {FH} and \overline {GI}

The length of IE = 3·x + 4

The length of EG = 5·x - 6

We have from segment addition postulate, \overline {GI} = IE + EG

The properties of a rectangle includes;

1) Each diagonal bisects the other diagonal into two

Therefore,  \overline {FH} bisects \overline {GI}, into two equal parts, from which we have;

IE = EG

\overline {GI} = IE + EG

3·x + 4 = 5·x - 6

4 + 6 = 5·x - 3·x = 2·x

10 = 2·x

∴ x = 10/2 = 5

From which we have;

IE = 3·x + 4 = 3 × 5 + 4 = 19 units

EG = 5·x - 6 = 5 × 5 - 6 = 19 units

\overline {GI} = IE + EG = 19 + 19 = 38 units

\overline {GI} = 38 units

2) The lengths of the two diagonals are equal. Therefore, the length of segment \overline {FH} is equal to the length of segment \overline {GI}

Mathematically, we have;

\overline {FH} = \overline {GI} = 38 units

∴ \overline {FH} = 38 units.

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3 years ago
I NEED HELP ASAP
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a) The equation V(m) = 8400 - 560\cdot m represents the discharge of the Grand Prismatic Spring.

b) The discharge of the Grand Prismatic Spring takes 15 minutes.

c) The remaining quantity after 7 minutes is 4480 gallons.

d) The hardness of cardboard is 2.

<h3>How to apply concepts of linear functions</h3>

a) In this case, the volume of water (V), in gallons, decreases <em>linearly</em> in time (m), in minutes. Then, we could model the situation by using the following expression:

V(m) = V_{o} - \dot V \cdot m (1)

Where:

  • V_{o} - Initial volume, in gallons.
  • \dot V - Discharge rate, in gallons per minute.

If we know that V_{o} = 8400\,gal and \dot V = 560\,\frac{gal}{min}, then the volume of the Grand Prismatic Spring is represented by this expression:

V(m) = 8400 - 560\cdot m (2)

The equation V(m) = 8400 - 560\cdot m represents the discharge of the Grand Prismatic Spring. \blacksquare

b) By (1) and V(m) = 0 we find the time required for discharge:

m = \frac{0 - 8400}{-560}

m = 15\,min

The discharge of the Grand Prismatic Spring takes 15 minutes. \blacksquare

c) The quantity of gallons remaining is found by evaluating the function for m = 7:

V(7) = 8400 - 560\cdot (7)

V(7) = 4480\,gal

The remaining quantity after 7 minutes is 4480 gallons. \blacksquare

d) According to Mohs scale, the hardness of feldspar is 6. The statement indicates the following relationship, as there is a constant relationship between both hardnesses:

y = 3\cdot x (3)

Where:

  • x - Hardness of cardboard.
  • y - Hardness of feldspar.

If we know that y = 6, then the hardness of cardboard is:

x = \frac{6}{3}

x = 2

The hardness of cardboard is 2. \blacksquare

To learn more on linear functions, we kindly invite to check this verified question: brainly.com/question/17058347

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C

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That leaves C. I think if you check it, you'll find it is right. sin(A) = cos(90 - A)

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