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mr Goodwill [35]
4 years ago
12

Find the length of the missing side of the triangle. The lengths of the triangles are 5m and 14m. The answer choices are:

Mathematics
2 answers:
Nezavi [6.7K]4 years ago
7 0
Two sides of a triangle are: 5, 14.
By triangle inequality the sum of each pair of sides must be > the third side.
x + 5 > 14
Subtract 5 from both sides.
x > 9

x + 14 > 5
Subtract 14 from both sides.
x > -9

5 + 14 > x
19 > x

x has to be greater than 9 but less than 19.
Letter A

torisob [31]4 years ago
4 0
I guess you mean 5m and 14m are the lengths of 2 sides of the triangle.

If  the length of any side is equal or greater than the sum of the other 2 sides then you can;t make a triangle.

So for example  19 cannot  the answer because 19 = 5 + 14 .  No triangle can be formed with sides that measure.
and 38 is greater than 14 + 5 so its cant be C.


The answer is A
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Alisa says it is easier to compare the numbers in set a (45,000, 1,025,680) instead of set b (492,111, 409,867). 1.What is one w
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Answer:

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3. Her strategy is the number which has the greatest ten thousand place is the greatest number because hundred thousand place has same digit in both numbers

Step-by-step explanation:

* <em>Lets explain how we can solve the problem </em>

- Alisa says it is easier to compare the numbers in set

 a (45,000, 1,025,680) instead of set b (492,111, 409,867)

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∵ Set b has two numbers both of them 6-digit

∴ We can decide whether Alissa conjecture is true or not

1. Set a has two numbers with different number of digits and set b

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-  Lets look to set a there are two numbers

  45,000 and 1,025,680

∵ The first number formed fro 5 digits and the greatest place value

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∵ The second number formed from 7 digits and the greatest place

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- <u><em>She did that without looking to the digits and compare them</em></u>

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  492,111 and 409,867

∵ The first number formed from six digits and the greatest place

   value is hundred thousands

∵ The second number formed from six digits and the greatest place

   value is hundred thousands

∴ The two numbers have same number of digits

∴ We must start to compare the digits from greatest place value

- <u><em>She must compare the corresponding digits to find the greatest one</em></u>

2. Alissa conjecture is true because she can compare the number in

  set a by counting the number of digits but in set b she must

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∵ The greatest place value is hundred thousands and the two

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  to the ten thousand place

∵ The ten thousands digit in the first number is 9

∵ The ten thousands digit in the second number is 0

∵ 9 > 0

∴ The first number is greater than the second number

3. Her strategy is the number which has the greatest ten thousand

   place is the greatest number because hundred thousand place

   has same digit in both numbers

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