Answer:
The answer is (4,-2)
Step-by-step explanation:
y=x-6
3x+2y=8
3x+2(x-6)=8
3x+2x-12=8 Combine like terms
3x+2x-12+12=8+12 add 12 to both sides then combine
5x=20→ x=4
then plug it in to y=x-6→y=4-6→y=-2
Awnser: y=1
Distribute
6=2(y+2)
6=2y+4
subtract 4 from both sides of the equation
6=2y+4
6-4=2y+4-4
simply
2=2y
then divide 2 from both sides
2/2=2y/2
y=1
Hope this helps :)
(a) When f is increasing the derivative of f is positive.
f'(x) = 15x^4 - 15x^2 > 0
15x^2(x^2 - 1)> 0
x^2 - 1 > 0 (The inequality doesn't flip sign since x^2 is positive)
x^2 > 1
Then f is increasing when x < -1 and x > 1.
(b) The f is concave upward when f''(x) > 0.
f''(x) = 60x^3 - 30x > 0
30x(2x^2 - 1) > 0
x(2x^2 - 1) > 0
x(x^2 - 1/2) > 0
x(x - 1/sqrt(2))(x + 1/sqrt(2)) > 0
There are four regions here. We will check if f''(x) > 0.
x < -1/sqrt(2): f''(-1) = -30 < 0
-1/sqrt(2) < x < 0: f''(-0.5) = 7.5 > 0
0 < x < 1/sqrt(2): f''(0.5) = -7.5 < 0
x > 1/sqrt(2): f''(1) = 30 > 0
Thus, f''(x) > 0 at -1/sqrt(2) < x < 0 and x > 1/sqrt(2).
Therefore, f is concave upward at -1/sqrt(2) < x < 0 and x > 1/sqrt(2).
(c) The horizontal tangents of f are at the points where f'(x) = 0
15x^2(x^2 - 1) = 0
x^2 = 1
x = -1 or x = 1
f(-1) = 3(-1)^5 - 5(-1)^3 + 2 = 4
f(1) = 3(1)^5 - 5(1)^3 + 2 = 0
Therefore, the tangent lines are y = 4 and y = 0.
Answer:
72 degrees
Step-by-step explanation:
2x+3x=180
5x=180
x=36
36*2=72
Answer:
-4 cot (-45)
Step-by-step explanation:
cos (390)
sin (330)
