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Answer is
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{(-5, 4), (-2, 3), (0, 1), (1, 5)}
(Third choice)
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Answer:
△GHD ≅ △EDH by SAS
Step-by-step explanation:
There are 3 types of congruences they are side angle side, side side side,
Angle side side.
We find that in the picture given above triangles GHF and EDF are having the following properties:
GH= ED(given)
angle GFH = angle EFD(vertically opposite angles)
But these two are sufficient to prove that the two triangles are congruent.
ii)
Triangles HFD and HFG
These two triangles have only HF = HF Hence cannot say congruent
iii) Consider triangles GHD and EDH
HD = HD (reflexive)
GH=ED(given)
Angle G = angle D (right angles)
Hence by SAS the two are congruent.
There is a theorem that says that this angle (formed by thre points on the circumference) is half such arc called EF.
We can deduct it as well.
1) Call O the center of the circle. The central angle (EOF) = arc EF = 151°
2) Draw a chord from F to D and other chord from D to E.
You have constructed two triangles, FOD and DOE.
3) Triangle FOD has two sides equals (because both are the radius of the circcle). Then, this is an isosceles triangle and it has two angles of the same measure. Call this measure a.
4) Triangle DOE is also isosceles, for the same reason explained in the poiint 3. Call the measure of its equal angles b.
5) The sum of the angles of the two triangles is 180° + 180 ° = 360°.
This is a + a + b + b + (360 - central angle) = 360°
=> 2a + 2b = central angle
=> 2(a+b) = cantral angle
=> (a+b) = central angle / 2 = 151° / 2 =71.5°
(a+b) is the angle that you are looking for.
Then the answer is 71.5°
Answer:
oof I also have the same question, that makes us 2