Solve for x: 6(4x+5)=3(x+8)+3 round to nearest hundredth

a citrus grower ships grape-fruit in boxes of 10 one season the grower shipped 20,400 boxes of grape- fruit how many were shiped

MA_775_DIABLO [31]

Just multiply 20,400 *10

8 0

3 years ago

Read 2 more answers

Find the sum of the first 20 terms of an arithmetic progression of which the third term is 55 and the last term is -98

ryzh [129]

The sum of first 20 arithmetic series $S_{20}=\frac{-3475}{16}$

Given:

Arithmetic series for 3rd term is 55

Arithmetic series for 7th term is -98

To find:

The sum of first 20 Arithmetic series

<u>Step by Step Explanation: </u>

Solution:

Formula for calculating arithmetic series

Arithmetic series=a+(n-1) d

Arithmetic series for 3rd term $a_{3}=a_{1}+(3-1) d$

$a_{1}+2 d=55$

Arithmetic series for 19th term is

$a_{19}=a_{1}+(19-1) d=-98$

$a_{19}+18 d=-98$

Subtracting equation 2 from 1

$\left[a_{19}+18 d=-98\right]+\left[a_{1}+2 d=55\right]$

16d=-98-55

16d=-153

$d=\frac{-153}{16}$

Also we know $a_{1}+2 d=55$

$a_{1}+2(-153 / 16)=55$

$a_{1}+(-153 / 8)=55$

$a_{1}=55+(153 / 8)$

$a_{1}=440+153 / 8$

$a_{1}=553 / 8$

First 20 terms of an AP

$a_{n=} a_{1}+(n-1) d$

$a_{20}=553 / 8+19(-153 / 16)$

$a_{20}=\{553 * 2 / 8 * 2\}-2907 / 16$

$a_{20}=[1106 / 16]-[2907 / 16]$

$a_{20}=-1801 / 16$

Sum of 20 Arithmetic series is

$S_{n}=n\left(a_{1}+a_{n}\right) / 2$

Substitute the known values in the above equation we get

$S_{20}=\left[\frac{20\left(\left(\frac{558}{8}\right)+\left(\frac{-1801}{16}\right)\right)}{2}\right]$

$S_{20}=\left[\frac{\left.20\left(\frac{1106}{16}\right)+\left(\frac{-1801}{16}\right)\right)}{2}\right]$

$S_{20}=10 \frac{(-695 / 16)}{2}$

$S_{20}=5\left[\frac{-695}{16}\right]$

$S_{20}=\frac{-3475}{16}$

Result:

Thus the sum of first 20 terms in an arithmetic series is $S_{20}=\frac{-3475}{16}$

7 0

3 years ago

at is another way to write the expression p⋅(10−2) ? (10⋅2)−p 10⋅2−p (10⋅2)⋅p (p⋅10)−(p⋅2)

Ostrovityanka [42]

Answer:

(p ⋅ 10) − (p ⋅ 2)

Step-by-step explanation:

Try to substitute "p" with any number.

Let's say p = 2

So

p ⋅ (10 − 2)

2 ⋅ (10 − 2)

2 ⋅ (8)

= 16

Now for the other equations

(p ⋅ 10) − (p ⋅ 2)

(2 ⋅ 10) − (2 ⋅ 2)

(20) - (4)

= 16

(10 ⋅ 2) − p

(10 ⋅ 2) − 2

(20 ) − 2

= 18

10 ⋅ 2 − p

10 ⋅ 2 − 2

20 - 2

= 18

(10 ⋅ 2) ⋅ p

(10 ⋅ 2) ⋅ 2

(20) ⋅ 2

= 40

Only (p ⋅ 10) − (p ⋅ 2) has the same result as p ⋅ (10 − 2).

Cheers

7 0

3 years ago

I need help with this. Can u plz show ur steps

evablogger [386]

74-17= 57 because if you subtract 10 from 74, it would be 64, then you need to subtract 7 from 64, which gives you 57.

9+7=16 because 10+7 would be 17, but since 9 is one less than 10, you need to subtract one from 17, which gives you 16.

17+(-30)=(-13) because adding 17 to -30 only brings up -30 to -13, and -30<-13.

-41+24=-17. Same reason as question 3, only different numbers.

-36+(-7)=-43 because adding two negatives together is like subtracting two positives from each other.

14+64=78 because adding 10 to 64 is 74 and 74+4=78.

-53-42=-95 because when you subtract a positive from a negative, it decreases the number even more.

-17-(-62)=45 because -62 is less than -17 and it is being subtracted from -17 so the answer becomes positive.

Hope this helps :)

6 0

4 years ago

I really hope you can see it if you can’t please ask me what it says cause I really need help

soldier1979 [14.2K]

Answer:

1. 20 cm^2

2. 40 cm^2

3. 14 cm^2

4 49 cm^2

Step-by-step explanation:

Area of triangle= 1/2(base)*(height)

Area of rectangle= (base)*(height)

1. 1/2(10)(4)=20

2. (8)(5)=40

3.1/2(4)(7)=14

4. (7)(7)=49

5 0

3 years ago